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大家好，我是编程新手，所以请原谅菜鸟问题...我尝试了所有方法来解决未定义的引用错误，但它一直向我抛出该错误我尝试使用指针“->”和“::”符号和还有点“。” 我应该做些什么？为什么不能编译？

这是我的 cpp 文件：

#include <cstdlib>
#include "account.hpp"

using namespace std;

int Account::getAccountNumber()
    {
        return accountNumber;
    }
double Account::getBalance()
    {
        return balance;
    }
void Account::createAccount(LinkedList<Account>& accountsList, string name, int idNumber)
{
...
    case 1:
       accountsList.addFront(newAcc); //Where the error occurs.
        break;
    case 2:
        do
        {
            cout << "\n\tWhich position would you like to insert the\n"
                 << "\tnew account into?\n"
                 << "\tPosition number: #";
            cin >> target;
            if (cin.fail())
            {
                cin.clear();
                cin.ignore(20,'\n');
                cout << "\n\n\tSorry, wrong input. Please enter a correct position.\n\n";
                system("pause");
            }
        }
        while(cin.fail());
        accountsList.addMiddle(newAcc, target); //and here
        break;
    case 3:
        accountsList.addEnd(newAcc); //and here
        break;
    }
    cout << "\n\n\tAccount Created Successfully\n\n"
         << accountsList; 
    system("pause");
}

这是我的.hpp

#ifndef ACCOUNT_HPP_INCLUDED
#define ACCOUNT_HPP_INCLUDED
#include "linkedlist.hpp"
#include "generic.hpp"

class Account : public GenericAccount
{
    int accountNumber;
    double balance;
public:
    Account(string name = "empty", int idNumber = 0, int accountNumber = 0, double balance = 0)
        :  GenericAccount(name, idNumber), accountNumber(accountNumber), balance(balance) {}
    int getAccountNumber();
    double getBalance();
    void createAccount(LinkedList<Account>&, string, int);
    void deposit(LinkedList<Account>&, Account&);
    void withdraw(LinkedList<Account>&, Account&);
    void displayAccount(LinkedList<Account>&, Account&);
    void deleteAccount(LinkedList<Account>&);

    friend istream& operator>> (istream& is, Account& x)
    {
        is >> x.accountNumber;
        return is;
    }

    friend ostream& operator << (ostream& os, Account& c)
    {
        os << "Account Number= " << c.getAccountNumber() << "\t"
           << "Balance= "<< c.getBalance() << endl;
        return os;
    }

    friend bool operator == (Account& a, Account& target)
    {
        return (a.getAccountNumber() == target.getAccountNumber());
    }

};


#endif // ACCOUNT_HPP_INCLUDED

完整的项目可以在这里下载以供参考 提前谢谢大家！

4

1 回答 1

0

我认为问题在于没有为帐户类型（实际上是任何类型）定义 addFront 方法。请参阅为什么模板只能在头文件中实现？以获得更好的解释。

在 .h 文件中移动内联 cpp 的内容应该可以解决问题。另一种选择是将 .cpp 文件重命名为 .inl 并将其包含在 linkedList.hpp 的底部

于 2013-08-24T17:34:59.927 回答