sql - 如何选择在列中出现次数较多的日期

Question

例如：

表是

日期账单金额
2013 年 12 月 6 日 200
2013 年 12 月 6 日 920
2013 年 6 月 15 日 300

输出是

日期账单金额
2013 年 12 月 6 日 1120
2013 年 6 月 15 日 300

Answer 1

这是SQLFiddle

 SELECT date, SUM(billamount)
   FROM tab1 GROUP BY date;

Answer 2

sqlfiddle

select d as "date",
       sum(amount) as "bill amount", 
       count(*) as "count" 
from T
group by d
having count(*) > 0 --change zero to occurrence number you wish
order by d;

sqlfiddle

Answer 3

使用group by来实现您的目标。

Answer 4

SELECT theDate, COUNT(theDate) AS NumOccurrences

FROM someTable GROUP BY theDate

HAVING ( COUNT(theDate) > 1 )