6

我有一个 ASP.net MVC 4.0 Web 应用程序，它使用户能够动态地将行添加到 html 表中。

在我看来：

$('.del').live('click', function () {
    id--;

    var rowCount = $('#options-table tr').length;

    if (rowCount > 2) {
         $(this).parent().parent().remove();
    }  
});

$('.add').live('click', function () {
    id++;
    var master = $(this).parents("table.dynatable");

    // Get a new row based on the prototype row
    var prot = master.find(".prototype").clone();
    prot.attr("class", "")
    prot.find(".id").attr("value", id);

    master.find("tbody").append(prot);
});

<table class="dynatable" id="options-table" width="100%" style="text-align:center" border="1">
    <tr class="prototype">
        <%:Html.EditorFor(m => Model.ChillerDetails)%> //referring to the template
    </tr>
    <thead>
</table>

在我的模板中：

<%@ Control  Language="C#" Inherits="System.Web.Mvc.ViewUserControl<GMIS.Models.GMISEBModels.ChillerPlantDetails>" %>

<div id="ChillerPlantDetails">
    <td><%: Html.EditorFor(m => m.ChillerAge) %></td>
    <td><%: Html.EditorFor(m => m.ChillerBrand) %></td>
    <td><%: Html.EditorFor(m => m.ChillerCapacity) %></td>
    <td><%: Html.EditorFor(m => m.ChillerRefrigerant) %></td>
    <td>
        <a href="#" class="add"><img src="<%= Url.Content("~/Content/Images/add.png") %>"/>&nbsp;<a href="#" class="del"><img src="<%= Url.Content("~/Content/Images/remove.png") %>"/>
    </td>
</div>

在我的模型中：

public class AddHealthCheckFormModel
{
    public List<ChillerPlantDetails> ChillerDetails { get; set; }
}

public class ChillerPlantDetails
{
    //[Required(ErrorMessage = "Please enter Chiller Capacity.")]
    [Display(Name = "Chiller Capacity")]
    public string ChillerCapacity { get; set; }

    //[Required(ErrorMessage = "Please enter Age of Chiller.")]
    [Display(Name = "Age of Chiller")]
    public string ChillerAge { get; set; }

    //[Required(ErrorMessage = "Please enter Chiller Brand.")]
    [Display(Name = "Chiller Brand")]
    public string ChillerBrand { get; set; }

    //[Required(ErrorMessage = "Please enter Chiller Refrigerant.")]
    [Display(Name = "Chiller Refrigerant")]
    public string ChillerRefrigerant { get; set; }
}

现在的问题是如何将动态添加的行中的数据捕获到我的控制器中并保存到数据库中？

4

1 回答 1

4

您可以使用以下视图，它将使用 HTTP Post 而不是 Ajax 添加新记录。将其替换为具有适当参数的 Ajax.BeginForm 将使用 Ajax 而不是普通的 post 请求。

@using (Html.BeginForm())
{
@Html.AntiForgeryToken()
@Html.ValidationSummary(true)
<table class="list-chiller-record">
    @for (int i = 0; i < this.Model.ChillerDetails.Count; i++)
    {
        if (i == 0)
        {
            <tr class="chiller-record-template" style="display:none">
                <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerAge)</td>
                <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerBrand)</td>
                <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerCapacity)</td>
                <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerRefrigerant)</td>
            </tr>    
        }

        <tr class="chiller-record">
            <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerAge)</td>
            <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerBrand)</td>
            <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerCapacity)</td>
            <td>@Html.EditorFor(x=>x.ChillerDetails[i].ChillerRefrigerant)</td>
        </tr>

    }
</table>
<br />
<input type="button" class="add-button" name="add" value="Add" />
<input type="submit" class="save-button" name="save" value="save" />
}

添加添加新行：

  <script type="text/javascript">
    $(document).ready(function () {
        var count = 2;
        $('.add-button').click(function () {
            count++;
            var template = $('.chiller-record-template').clone()
            template.find('input[type=text]').val('');
            $.each(template.find('input[type=text]'), function () {
                var name = $(this).attr('name');
                name = name.replace('0', count - 1);
                $(this).attr('name', name);
            });

            $('.list-chiller-record').append(template);
            template.removeClass('chiller-record-template').addClass('chiller-record').show();
        })
    });
 </script>

您的操作可能是这样的：

 [HttpPost]
    public ActionResult AddHealthCheck(AddHealthCheckFormModel model)
    {
        if (ModelState.IsValid)
        {
            HealthCheckRepository healthCheckRepository = new HealthCheckRepository();
            healthCheckRepository.save(model);
        }

        return this.View(model);
    }

在存储库中，您实际上可以将数据保存在数据库中。您可以为此使用 EF 或任何其他 ORM。

于 2013-08-24T07:54:50.800 回答