0

我需要将各种参数传递到具有 unix 格式的.cmd 文件中

file.cmd -Configuration=value -Source=value -flag

但是，我试试这个：

StartLocal

@ECHO off
CLS

SETLOCAL
SET CMDLINE=%*
SET Configuration=
SET Source=
SET BADARGS=
SET VALIDATION=
GOTO main

:SplitArgs
  echo SplitArgs(%*)
  if "%*" NEQ "" (
    for /F "tokens=1,2,* delims== " %%i in ("%*") do call :AssignKeyValue %%i %%j & call :SplitArgs %%k
  )
  goto :eof

:AssignKeyValue
  echo   AssignKeyValue(%1, %2)
  if /i %1==-Configuration (
    SET Configuration=%2
  ) else if /i %1==-Source (
    SET Source=%2
  ) else (
    REM Append unrecognised [key,value] to BADARGS
    echo Unknown KEY %1
    SET BADARGS=%BADARGS%[%1, %2]
  )
  goto :eof

:Validate
 echo Validating
 SET VALIDATION=FAIL
 if defined Configuration (
   echo   -Configuration ok
   if defined Source (
     echo   -Source ok
       if NOT defined BADARGS (
         SET VALIDATION=SUCCESS
       )
   )
 )
 goto :eof

:main
  cls
  call :SplitArgs %CMDLINE%
  call :Validate
  if "%VALIDATION%" EQU "SUCCESS" (
    ECHO -Configuration = %Configuration%
    ECHO -Source = %Source%
  )

但是我有一个问题，因为当我在这种模式下写一个参数时

file.cmd 源=值

总是取值，我需要验证这个，一些想法......谢谢

4

1 回答 1

3

尝试这个：

file.cmd "Source=value"
于 2013-08-23T19:10:01.353 回答