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我是 jQgrid 的新手。我的 web 服务以 JSON 响应 jQgrid 提供列数据类型的附加数据，而不是页面、总计、记录和行。我的 JSON 字符串如下：

{"d":
{"__type":"iReg.JQGrid","page":1,"total":20,"records":194,
"rows":[{"id":"560013cb-9c86-4471-8379-031cea98c507","cell":["TENDERSTATUS","Won - PO Received",""]},
{"id":"88170912-1b2a-441f-9002-0be93e0bcd8f","cell":["ORDERTYPE","Development","Development order"]},
{"id":"e67284f7-4f42-456b-b1a9-04cabaf77305","cell":["ORDERSTATUS","Pending","Pending - Default status"]},
{"id":"14ba5274-e60d-441a-887b-0a999f5a4e4c","cell":["ITEMPROCESS_STEP","Blend","Blending Process"]},
{"id":"aa7857a7-de94-42bf-8075-0ab3d3d65bf1","cell":["EXPENSE_SUBTYPE","Stationary","Stationary"]},
{"id":"b0ab6cd8-4e21-4350-8970-03cd4aaa6d61","cell":["EXPENSE_SUBTYPE","Food","Food"]},
{"id":"57a36caa-01f8-489f-b469-0a803d25c1c6","cell":["DOCUMENT_CATEGORY","Acceptance Note","Acceptance Note"]},
{"id":"9d39f81e-a524-49e8-a0b5-09a865533913","cell":["DESIGNATION","Sales Engineer","Sales Engineer"]},
{"id":"880a2441-e0db-4cda-978c-01387c969df6","cell":["CITY","Noida","U.P."]},
{"id":"0000a8c4-82b8-4ad6-a122-00938307e269","cell":["AIPRIORITY","Medium","Medium priority for action item"]}],
"coldatatypes":["String","String","String"]
}}

在上面的 JSON 字符串中，coldatatypes是我想在 jqgrid 中读取的附加数据，并希望将其放入一个变量中，以便我可以将它用于我的其他目的。可能吗？？

.cs 文件：读取和存储值的属性

   public class JQGrid
   {
      ........
      ........ 
      public List<string> coldatatype { get; set; }
       public JQGrid()
       {
           .......
           coldatatype = new List<string>();
       }
    }
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