2

在我的 rails 应用程序中，我有两个表 -device_ports和circuits. 我的目标是获取表列中device_ports未id使用的列表。physical_port_idcircuits

我之前在其他表上做过类似的事情，但在这里我的查询只返回一行，而它应该返回 23 行——这个设备有 24 个设备端口，一个正在使用中。

select id, name, device_id, multiuse
from device_ports
where (device_id = 6 and multiuse = 1)
or device_ports.id not in (select physical_port_id from circuits)

因此，此查询获取所有多用途端口（因此，即使在外键中引用了 id，仍应返回此行）并且还应获取 device_id 为 6 但未在电路中引用但只有多用途行的所有行被退回。

查询的结果是

id  | name   | device_id | multiuse
------------------------------------
268 | test-1 |     6     |    1

我确实尝试创建一个 sql fiddle，但构建似乎超时。

CREATE TABLE `device_ports` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `device_id` int(11) DEFAULT NULL,
  `name` tinytext,
  `speed` tinytext,
  `multiuse` tinyint(1) DEFAULT NULL,
  `created_at` datetime DEFAULT NULL,
  `updated_at` datetime DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `id` (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=291 DEFAULT CHARSET=latin1;

INSERT INTO `device_ports` (`id`, `device_id`, `name`, `speed`, `multiuse`, `created_at`, `updated_at`)
*emphasized text*VALUES
(1, 1, 'Test Device Port', '100', 0, NULL, NULL),
(2, 1, 'Test Port 2', '300', 1, NULL, NULL),
(289, 6, 'test-22', '100', 0, NULL, NULL),
(290, 6, 'test-23', '100', 0, NULL, NULL),
(288, 6, 'test-21', '100', 0, NULL, NULL),
(287, 6, 'test-20', '100', 0, NULL, NULL),
(286, 6, 'test-19', '100', 0, NULL, NULL),
(284, 6, 'test-17', '100', 0, NULL, NULL),
(285, 6, 'test-18', '100', 0, NULL, NULL),
(283, 6, 'test-16', '100', 0, NULL, NULL),
(282, 6, 'test-15', '100', 0, NULL, NULL),
(281, 6, 'test-14', '100', 0, NULL, NULL),
(280, 6, 'test-13', '100', 0, NULL, NULL),
(279, 6, 'test-12', '100', 0, NULL, NULL),
(278, 6, 'test-11', '100', 0, NULL, NULL),
(277, 6, 'test-10', '100', 0, NULL, NULL),
(276, 6, 'test-9', '100', 0, NULL, NULL),
(275, 6, 'test-8', '100', 0, NULL, NULL),
(274, 6, 'test-7', '100', 0, NULL, NULL),
(273, 6, 'test-6', '100', 0, NULL, NULL),
(272, 6, 'test-5', '100', 0, NULL, NULL),
(271, 6, 'test-4', '100', 0, NULL, NULL),
(270, 6, 'test-3', '100', 0, NULL, NULL),
(269, 6, 'test-2', '100', 0, NULL, NULL),
(268, 6, 'test-1', '100', 1, NULL, NULL),
(267, 6, 'test-0', '100', 0, NULL, NULL);


CREATE TABLE `circuits` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `organisation_id` int(11) DEFAULT NULL,
  `physical_port_id` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=248 DEFAULT CHARSET=latin1;

INSERT INTO `circuits` (`id`, `organisation_id`, `physical_port_id`)
VALUES (1, 125, 267);
4

2 回答 2

7

您可以尝试使用 LEFT OUTER JOIN：

SELECT DISTINCT d.id, d.name, d.device_id, d.multiuse
 FROM device_ports d
 LEFT OUTER JOIN circuits c ON c.physical_port_id = d.id 
WHERE 
 (c.physical_port_id IS NULL AND d.device_id = 6) 
 OR (d.multiuse = 1 AND d.device_id = 6) 
 ORDER BY d.id

这个查询有几种技术，看看什么是 NOT EXISTS vs. NOT IN vs. LEFT JOIN WHERE IS NULL 之间的区别？.

于 2013-08-23T11:00:05.623 回答
0 
SELECT p.* 
  FROM device_ports p 
  LEFT 
  JOIN circuits c 
    ON c.physical_port_id = p.id 
 WHERE p.device_id = 6 
   AND multiuse = 1 
   AND c.id IS NULL;
于 2013-08-23T11:00:40.877 回答