c++ - 如何在 Windows Forms/C++ 中将文本或数字旋转 90°？

Question

我想在 Windows 窗体应用程序 Visual Studio 2010 (C++) 中将文本块或数字旋转 90°。是否有捷径可寻？

Answer 1

您必须创建一个LOGFONT并使用lfEscapement和lfOrientation的值，如下所示：

SetGraphicsMode(hdc, GM_ADVANCED);

LOGFONT font          = {0};

font.lfHeight         = 0;
font.lfWidth          = 0;
font.lfEscapement     = 900; // here
font.lfOrientation    = 900; // and here
font.lfWeight         = 0;
font.lfItalic         = false;
font.lfUnderline      = false;
font.lfStrikeOut      = false;
font.lfCharSet        = DEFAULT_CHARSET;
font.lfOutPrecision   = OUT_DEFAULT_PRECIS;
font.lfClipPrecision  = CLIP_DEFAULT_PRECIS;
font.lfQuality        = CLEARTYPE_QUALITY;
font.lfPitchAndFamily = DEFAULT_PITCH | FF_DONTCARE;

auto newfont = CreateFontIndirect(&font);
auto oldfont = SelectObject(hdc, newfont);

/* do actual drawing here */

SelectObject(hdc, oldfont);

SetGraphicsMode(hdc, GM_COMPATIBLE);

DeleteObject(newfont);

Answer 2

String theString = "90 Degree Rotated Text";
SizeF sz = e.Graphics.VisibleClipBounds.Size;
//Offset the coordinate system so that point (0, 0) is at the center of the desired area.
e.Graphics.TranslateTransform(sz.Width / 2, sz.Height / 2);

//Rotate the Graphics object.
e.Graphics.RotateTransform(90);
sz = e.Graphics.MeasureString(theString, this.Font);

//Offset the Drawstring method so that the center of the string matches the center.
e.Graphics.DrawString(theString, this.Font,
Brushes.Black, -(sz.Width/2), -(sz.Height/2));

//Reset the graphics object Transformations.
e.Graphics.ResetTransform();

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