497

如何删除unique row id存在的重复行?

我的桌子是

col1  col2 col3 col4 col5 col6 col7
john  1    1    1    1    1    1 
john  1    1    1    1    1    1
sally 2    2    2    2    2    2
sally 2    2    2    2    2    2

我想在重复删除后留下以下内容:

john  1    1    1    1    1    1
sally 2    2    2    2    2    2

我尝试了一些查询,但我认为它们取决于有一个行 ID,因为我没有得到想要的结果。例如:

DELETE
FROM table
WHERE col1 IN (
    SELECT id
    FROM table
    GROUP BY id
    HAVING (COUNT(col1) > 1)
)
4

23 回答 23

886

我喜欢 CTE,ROW_NUMBER因为两者结合起来让我们可以看到哪些行被删除(或更新),因此只需将其更改DELETE FROM CTE...SELECT * FROM CTE

WITH CTE AS(
   SELECT [col1], [col2], [col3], [col4], [col5], [col6], [col7],
       RN = ROW_NUMBER()OVER(PARTITION BY col1 ORDER BY col1)
   FROM dbo.Table1
)
DELETE FROM CTE WHERE RN > 1

DEMO (结果不同;我认为这是由于您的拼写错误)

COL1    COL2    COL3    COL4    COL5    COL6    COL7
john    1        1       1       1       1       1
sally   2        2       2       2       2       2

此示例通过单个列确定重复项,col1因为PARTITION BY col1. 如果要包含多个列,只需将它们添加到PARTITION BY

ROW_NUMBER()OVER(PARTITION BY Col1, Col2, ... ORDER BY OrderColumn)
于 2013-08-22T20:55:50.640 回答
181

我更喜欢 CTE 从 sql server 表中删除重复的行

强烈推荐关注这篇文章 :: http://codaffection.com/sql-server-article/delete-duplicate-rows-in-sql-server/

通过保持原始

WITH CTE AS
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY col1,col2,col3 ORDER BY col1,col2,col3) AS RN
FROM MyTable
)

DELETE FROM CTE WHERE RN<>1

不保留原创

WITH CTE AS
(SELECT *,R=RANK() OVER (ORDER BY col1,col2,col3)
FROM MyTable)
 
DELETE CTE
WHERE R IN (SELECT R FROM CTE GROUP BY R HAVING COUNT(*)>1)
于 2016-08-14T02:46:00.640 回答
70

不使用CTEROW_NUMBER()您可以通过使用 group by withMAX函数来删除记录,这里是示例

DELETE
FROM MyDuplicateTable
WHERE ID NOT IN
(
SELECT MAX(ID)
FROM MyDuplicateTable
GROUP BY DuplicateColumn1, DuplicateColumn2, DuplicateColumn3)
于 2016-10-30T07:22:57.113 回答
25

如果你没有引用,比如外键,你可以这样做。在测试概念证明并且测试数据被重复时,我经常这样做。

SELECT DISTINCT [col1],[col2],[col3],[col4],[col5],[col6],[col7]

INTO [newTable]

FROM [oldTable]

进入对象资源管理器并删除旧表。

用旧表的名称重命名新表。

于 2016-01-26T18:54:34.340 回答
18
DELETE from search
where id not in (
   select min(id) from search
   group by url
   having count(*)=1

   union

   SELECT min(id) FROM search
   group by url
   having count(*) > 1
)
于 2014-08-11T14:55:13.623 回答
10

有两种解决方案mysql

A)DELETE JOIN使用语句删除重复行

DELETE t1 FROM contacts t1
INNER JOIN contacts t2 
WHERE 
    t1.id < t2.id AND 
    t1.email = t2.email;

此查询引用了两次联系人表,因此,它使用表别名t1t2.

输出是:

1 个查询正常,4 行受影响(0.10 秒)

如果要删除重复行并保留lowest id,可以使用以下语句:

DELETE c1 FROM contacts c1
INNER JOIN contacts c2 
WHERE
    c1.id > c2.id AND 
    c1.email = c2.email;

   

B)使用中间表删除重复行

下面显示了使用中间表删除重复行的步骤:

    1. 创建一个新表,其结构与要删除重复行的原始表相同。

    2. 将原始表中的不同行插入到直接表中。

    3. 将原始表中的不同行插入到直接表中。

 

步骤 1. 创建一个与原表结构相同的新表:

CREATE TABLE source_copy LIKE source;

步骤 2. 将原始表中的不同行插入到新表中:

INSERT INTO source_copy
SELECT * FROM source
GROUP BY col; -- column that has duplicate values

步骤 3. 删除原始表并将直接表重命名为原始表

DROP TABLE source;
ALTER TABLE source_copy RENAME TO source;

来源:http ://www.mysqltutorial.org/mysql-delete-duplicate-rows/

于 2019-11-04T04:53:58.953 回答
10

删除所有重复项,但最先删除(使用最小 ID)

应该在其他 SQL 服务器(如 Postgres)中同样工作:

DELETE FROM table
WHERE id NOT IN (
   select min(id) from table
   group by col1, col2, col3, col4, col5, col6, col7
)
于 2020-06-20T15:02:05.883 回答
10

请参阅下面的删除方式。

Declare @table table
(col1 varchar(10),col2 int,col3 int, col4 int, col5 int, col6 int, col7 int)
Insert into @table values 
('john',1,1,1,1,1,1),
('john',1,1,1,1,1,1),
('sally',2,2,2,2,2,2),
('sally',2,2,2,2,2,2)

创建了一个名为的示例表@table并使用给定的数据加载它。

在此处输入图像描述

Delete  aliasName from (
Select  *,
        ROW_NUMBER() over (Partition by col1,col2,col3,col4,col5,col6,col7 order by col1) as rowNumber
From    @table) aliasName 
Where   rowNumber > 1

Select * from @table

在此处输入图像描述

注意:如果您要给出部分中的所有列Partition by,则order by没有太大意义。

我知道,这个问题是三年前提出的,我的回答是蒂姆发布的另一个版本,但发布只是以防万一它对任何人都有帮助。

于 2016-09-28T10:11:31.777 回答
7

Microsoft 有一个关于如何删除重复项的非常简洁的指南。查看 http://support.microsoft.com/kb/139444

简而言之,当您只有几行要删除时,这是删除重复项的最简单方法:

SET rowcount 1;
DELETE FROM t1 WHERE myprimarykey=1;

myprimarykey是行的标识符。

我设置rowcount为 1 因为我只有两行重复。如果我有 3 行重复,那么我会将rowcount设置为 2,以便它删除它看到的前两个,并且只在表 t1 中留下一个。

于 2014-06-05T14:41:35.693 回答
7

在 sql server 中可以通过多种方式完成,最简单的方法是:将重复行表中的不同行插入到新的临时表中。然后从重复行表中删除所有数据,然后从没有重复的临时表中插入所有数据,如下所示。

select distinct * into #tmp From table
   delete from table
   insert into table
   select * from #tmp drop table #tmp

   select * from table

使用公用表表达式(CTE)删除重复行

With CTE_Duplicates as 
(select id,name , row_number() 
over(partition by id,name order by id,name ) rownumber  from table  ) 
delete from CTE_Duplicates where rownumber!=1
于 2019-07-19T16:25:17.283 回答
5

尝试使用:

SELECT linkorder
    ,Row_Number() OVER (
        PARTITION BY linkorder ORDER BY linkorder DESC
        ) AS RowNum
FROM u_links

在此处输入图像描述

于 2019-03-01T11:11:41.217 回答
4

在尝试了上面建议的解决方案后,它适用于中小型表。我可以为非常大的表建议该解决方案。因为它在迭代中运行。

  1. 删除所有依赖视图LargeSourceTable
  2. 您可以使用sql managment studio找到依赖关系,右键单击表并单击“查看依赖关系”
  3. 重命名表:
  4. sp_rename 'LargeSourceTable', 'LargeSourceTable_Temp'; GO
  5. 再次创建LargeSourceTable,但现在,添加一个主键,其中包含定义重复项的所有列添加WITH (IGNORE_DUP_KEY = ON)
  6. 例如:

    CREATE TABLE [dbo].[LargeSourceTable] ( ID int IDENTITY(1,1), [CreateDate] DATETIME CONSTRAINT [DF_LargeSourceTable_CreateDate] DEFAULT (getdate()) NOT NULL, [Column1] CHAR (36) NOT NULL, [Column2] NVARCHAR (100) NOT NULL, [Column3] CHAR (36) NOT NULL, PRIMARY KEY (Column1, Column2) WITH (IGNORE_DUP_KEY = ON) ); GO

  7. 再次为新创建的表创建您首先删除的视图

  8. 现在,运行以下 sql 脚本,您将看到每页 1,000,000 行的结果,您可以更改每页的行数以更频繁地查看结果。

  9. 请注意,我设置了IDENTITY_INSERTon 和 off,因为其中一个列包含自动增量 id,我也在复制

SET IDENTITY_INSERT LargeSourceTable ON DECLARE @PageNumber AS INT, @RowspPage AS INT DECLARE @TotalRows AS INT declare @dt varchar(19) SET @PageNumber = 0 SET @RowspPage = 1000000 select @TotalRows = count (*) from LargeSourceTable_TEMP

While ((@PageNumber - 1) * @RowspPage < @TotalRows )
Begin
    begin transaction tran_inner
        ; with cte as
        (
            SELECT * FROM LargeSourceTable_TEMP ORDER BY ID
            OFFSET ((@PageNumber) * @RowspPage) ROWS
            FETCH NEXT @RowspPage ROWS ONLY
        )

        INSERT INTO LargeSourceTable 
        (
             ID                     
            ,[CreateDate]       
            ,[Column1]   
            ,[Column2] 
            ,[Column3]       
        )       
        select 
             ID                     
            ,[CreateDate]       
            ,[Column1]   
            ,[Column2] 
            ,[Column3]       
        from cte

    commit transaction tran_inner

    PRINT 'Page: ' + convert(varchar(10), @PageNumber)
    PRINT 'Transfered: ' + convert(varchar(20), @PageNumber * @RowspPage)
    PRINT 'Of: ' + convert(varchar(20), @TotalRows)

    SELECT @dt = convert(varchar(19), getdate(), 121)
    RAISERROR('Inserted on: %s', 0, 1, @dt) WITH NOWAIT
    SET @PageNumber = @PageNumber + 1
End

SET IDENTITY_INSERT LargeSourceTable OFF

于 2018-08-15T12:40:23.407 回答
2
-- this query will keep only one instance of a duplicate record.
;WITH cte
     AS (SELECT ROW_NUMBER() OVER (PARTITION BY col1, col2, col3-- based on what? --can be multiple columns
                                       ORDER BY ( SELECT 0)) RN
         FROM   Mytable)



delete  FROM cte
WHERE  RN > 1
于 2016-10-25T08:16:21.383 回答
2

您需要根据字段对重复记录进行分组,然后保留其中一条记录并删除其余记录。例如:

DELETE prg.Person WHERE Id IN (
SELECT dublicateRow.Id FROM
(
select MIN(Id) MinId, NationalCode
 from  prg.Person group by NationalCode  having count(NationalCode ) > 1
 ) GroupSelect
 JOIN  prg.Person dublicateRow ON dublicateRow.NationalCode = GroupSelect.NationalCode 
 WHERE dublicateRow.Id <> GroupSelect.MinId)
于 2019-01-23T04:47:47.103 回答
2

从巨大的(几百万条记录)表中删除重复项可能需要很长时间。我建议您对选定行的临时表进行批量插入,而不是删除。

--REWRITING YOUR CODE(TAKE NOTE OF THE 3RD LINE) WITH CTE AS(SELECT NAME,ROW_NUMBER() 
OVER (PARTITION BY NAME ORDER BY NAME) ID FROM @TB) SELECT * INTO #unique_records FROM 
CTE WHERE ID =1;
于 2019-08-15T10:47:03.180 回答
2

这可能对您的情况有所帮助

DELETE t1 FROM table t1 INNER JOIN table t2 WHERE t1.id > t2.id AND t1.col1 = t2.col1 
于 2020-07-07T17:16:47.310 回答
1

参考 https://support.microsoft.com/en-us/help/139444/how-to-remove-duplicate-rows-from-a-table-in-sql-server

删除重复的想法涉及

  • a) 保护那些不重复的行
  • b) 保留一起限定为重复的许多行之一。

一步步

  • 1)首先确定满足重复定义的行并将它们插入到临时表中,例如 #tableAll 。
  • 2)在临时表中选择非重复(单行)或不同的行,例如#tableUnique。
  • 3) 从加入#tableAll 的源表中删除以删除重复项。
  • 4) 将#tableUnique 中的所有行插入源表。
  • 5) 删除#tableAll 和#tableUnique
于 2017-09-19T19:01:49.353 回答
1

如果您能够临时向表中添加一列,这是一个对我有用的解决方案:

ALTER TABLE dbo.DUPPEDTABLE ADD RowID INT NOT NULL IDENTITY(1,1)

然后使用 MIN 和 GROUP BY 的组合执行 DELETE

DELETE b
FROM dbo.DUPPEDTABLE b
WHERE b.RowID NOT IN (
                     SELECT MIN(RowID) AS RowID
                     FROM dbo.DUPPEDTABLE a WITH (NOLOCK)
                     GROUP BY a.ITEM_NUMBER,
                              a.CHARACTERISTIC,
                              a.INTVALUE,
                              a.FLOATVALUE,
                              a.STRINGVALUE
                 );

验证 DELETE 是否正确执行:

SELECT a.ITEM_NUMBER,
    a.CHARACTERISTIC,
    a.INTVALUE,
    a.FLOATVALUE,
    a.STRINGVALUE, COUNT(*)--MIN(RowID) AS RowID
FROM dbo.DUPPEDTABLE a WITH (NOLOCK)
GROUP BY a.ITEM_NUMBER,
    a.CHARACTERISTIC,
    a.INTVALUE,
    a.FLOATVALUE,
    a.STRINGVALUE
ORDER BY COUNT(*) DESC 

结果应该没有计数大于 1 的行。最后,删除 rowid 列:

ALTER TABLE dbo.DUPPEDTABLE DROP COLUMN RowID;
于 2018-03-23T12:52:03.920 回答
1
with myCTE
as

(
select productName,ROW_NUMBER() over(PARTITION BY productName order by slno) as Duplicate from productDetails
)
Delete from myCTE where Duplicate>1
于 2016-10-09T18:41:20.933 回答
0

另一种在不丢失信息的情况下删除重复行的方法如下:

delete from dublicated_table t1 (nolock)
join (
    select t2.dublicated_field
    , min(len(t2.field_kept)) as min_field_kept
    from dublicated_table t2 (nolock)
    group by t2.dublicated_field having COUNT(*)>1
) t3 
on t1.dublicated_field=t3.dublicated_field 
    and len(t1.field_kept)=t3.min_field_kept
于 2014-06-30T08:41:52.897 回答
0

哦,哇,准备好所有这些答案让我觉得很愚蠢,它们就像专家对所有 CTE 和临时表等的回答。

我所做的只是使用 MAX 聚合 ID 列。

DELETE FROM table WHERE col1 IN (
    SELECT MAX(id) FROM table GROUP BY id HAVING ( COUNT(col1) > 1 )
)

注意:您可能需要多次运行它才能删除重复,因为这一次只会删除一组重复的行。

于 2018-07-17T12:52:45.947 回答
0
DECLARE @TB TABLE(NAME VARCHAR(100));
INSERT INTO @TB VALUES ('Red'),('Red'),('Green'),('Blue'),('White'),('White')
--**Delete by Rank**
;WITH CTE AS(SELECT NAME,DENSE_RANK() OVER (PARTITION BY NAME ORDER BY NEWID()) ID FROM @TB)
DELETE FROM CTE WHERE ID>1
SELECT NAME FROM @TB;
--**Delete by Row Number** 
;WITH CTE AS(SELECT NAME,ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY NAME) ID FROM @TB)
DELETE FROM CTE WHERE ID>1;
SELECT NAME FROM @TB;
于 2019-08-05T12:29:28.413 回答
0
DELETE FROM TBL1  WHERE ID  IN
(SELECT ID FROM TBL1  a WHERE ID!=
(select MAX(ID) from TBL1  where DUPVAL=a.DUPVAL 
group by DUPVAL
having count(DUPVAL)>1))
于 2019-12-03T07:23:40.380 回答