1

我正在尝试通过连接到我的数据库并验证用户名和密码来制作登录表单，我正在使用 JSON 方法

 public class LoginActivity extends Activity {
 JSONParser jParser = new JSONParser();
 private static String url_login = "http://192.168.1.81:80get_all_usernames.php";
 JSONArray admin = null;
 int i;


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.adminlogin);
}


 public void enter(View v)
 {

      TextView user= (TextView) findViewById (R.id.user);
      TextView pass= (TextView) findViewById (R.id.pass);
      CharSequence usr=  user.getText();
      CharSequence pwd=pass.getText();
      Log.i("",""+usr);
      Log.i("",""+pwd);
      ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();
     JSONObject json = jParser.makeHttpRequest(url_login, "GET",param);

      Log.i("","fjefejjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj");
     try{
       int success = json.getInt("success");

       if(success == 1){
    admin = json.getJSONArray("admin");
        for(i=0;i<admin.length();i++){
        final JSONObject c = admin.getJSONObject(i);
        String real_user=c.getString("username");
        String real_password= c.getString("password");
            if(usr==real_user && pwd==real_password)
            {
     Log.i("success","login sucessfull-----------------------");
        }
     else{
       Log.i("fail","Login failed ----------------------------------");
         }
     }}
    }catch(Exception e){
      }
   }

      }

它一直在该行返回错误： JSONObject json = jParser.makeHttpRequest(url_login, "GET",param); 有人可以帮我吗？

提前谢谢你，拉尔夫

4

2 回答 2

1

Your URL is wrong:

http://192.168.1.81:80get_all_usernames.php

should be:

http://192.168.1.81:80/get_all_usernames.php

Also, for http you do not need to specify port 80. That is the default.

于 2013-08-22T16:46:24.350 回答
1

First of All Correct your URL and then Use HttpClient and AsynsTask for Network Request.

public final class HttpTask extends  AsyncTask<Strin param, Void param, String param> {

private HttpClient mHc = new DefaultHttpClient();

@Override
protected String doInBackground(String... params) {

   HttpClient client = new DefaultHttpClient();
   HttpPost request = new Http(params[0]);
   try
   {
       // Add params using Name Value Pair

       HttpResponse response = client.execute(request);
       HttpEntity entity = response.getEntity();
       InputStream inputStream = entity.getContent();
       //Parse Response from InputStream  
   }

   // return  "Success" or "fail";
}

@Override
protected void onProgressUpdate(Boolean... progress) {


}

@Override
protected void onPostExecute(String result) {

}

}

于 2013-08-22T16:49:07.840 回答