3

在我的代码中，我从 URL 获取数据。当 URL 包含空格时，它在浏览器中可以正常工作，但是当我通过应用程序访问时，由于 URL 中的空格而显示错误。

我的logcat在下面。

http://XXX.XX.XX.XX/~school/index.php/api/index/getschools?mg=Pre-Ks and CDC Lunch  
 menu&sl=Elementary


              try {

        HttpClient client = new DefaultHttpClient();
        HttpConnectionParams
                .setConnectionTimeout(client.getParams(), 15000);
        HttpConnectionParams.setSoTimeout(client.getParams(), 15000);
        HttpUriRequest request = new HttpGet(SelectMenuAPI);
        HttpResponse response = client.execute(request);
        InputStream atomInputStream = response.getEntity().getContent();
        BufferedReader in = new BufferedReader(new InputStreamReader(
                atomInputStream));

        String line;
        String str = "";
        while ((line = in.readLine()) != null) {
            str += line;
        }






        }



    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        // IOConnect = 1;
        e.printStackTrace();
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
  }















               /AndroidRuntime(4885): FATAL EXCEPTION: main
 E/AndroidRuntime(4885): java.lang.RuntimeException: Unable to start activity  
 ComponentInfo{com.schoollunchapp/com.schoollunchapp.SecondStep}:    
java.lang.IllegalArgumentException: Illegal character in query at index 69: 
http://XXX.XX.XX.XX/~school/index.php/api/index/getschools?mg=Pre-Ks and CDC Lunch 
  menu&sl=Elementary

08-23 00:46:18.174: E/AndroidRuntime(4885):     at    
android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2663)

08-23 00:46:18.174: E/AndroidRuntime(4885):     at 
  android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2679)

08-23 00:46:18.174: E/AndroidRuntime(4885):     at   
 android.app.ActivityThread.access$2300(ActivityThread.java:125)
  08-23 00:46:18.174: E/AndroidRuntime(4885):   at  
 android.app.ActivityThread$H.handleMessage(ActivityThread.java:2033)

 08-23 00:46:18.174: E/AndroidRuntime(4885):    at     
 android.os.Handler.dispatchMessage(Handler.java:99)
  08-23 00:46:18.174: E/AndroidRuntime(4885):   at  \    
  android.os.Looper.loop(Looper.java:123)
   08-23 00:46:18.174: E/AndroidRuntime(4885):  at  
   android.app.ActivityThread.main(ActivityThread.java:4627)
  08-23 00:46:18.174: E/AndroidRuntime(4885):   at  
   java.lang.reflect.Method.invokeNative(Native Method)
   08-23 00:46:18.174: E/AndroidRuntime(4885):  at  
   java.lang.reflect.Method.invoke(Method.java:521)
     08-23 00:46:18.174: E/AndroidRuntime(4885):    at  
  com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:868)

  08-23 00:46:18.174: E/AndroidRuntime(4885):   at    
 com.android.internal.os.ZygoteInit.main(ZygoteInit.java:626)
 08-23 00:46:18.174: E/AndroidRuntime(4885):    at     
 dalvik.system.NativeStart.main(Native Method)

 08-23 00:46:18.174: E/AndroidRuntime(4885): Caused by:   
 java.lang.IllegalArgumentException: Illegal character in query at index 69:  
 http://XXX.XX.XX.XX/~school/index.php/api/index/getschools?mg=Pre-Ks and CDC Lunch  
 menu&sl=Elementary
 08-23 00:46:18.174: E/AndroidRuntime(4885):    at    
  java.net.URI.create(URI.java:970)
  08-23 00:46:18.174: E/AndroidRuntime(4885):   at  
 org.apache.http.client.methods.HttpGet.<init>(HttpGet.java:75)

 08-23 00:46:18.174: E/AndroidRuntime(4885):    at  
 com.schoollunchapp.SecondStep.parseJSONData(SecondStep.java:119)

 08-23 00:46:18.174: E/AndroidRuntime(4885):    at   
   com.schoollunchapp.SecondStep.onCreate(SecondStep.java:96)

    08-23 00:46:18.174: E/AndroidRuntime(4885):     at    
  android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1047)
 08-23 00:46:18.174: E/AndroidRuntime(4885):    at  
  android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2627)
4

2 回答 2

4

试试这条线：

String URL = URLEncoder.encode("URL", "UTF-8");

或者

String URL = URL.replace(" ", "%20");

希望能帮助到你！！

于 2013-08-22T12:54:11.107 回答
2

使用 android .replace 调用将您的空格替换为 %20。

String stringurl = "http://mysite.com/pictures of stuff";
stringurl = stringurl.replace(" ", "%20");

URL 不喜欢空格，填充符会消除您的问题。这样做是一个好习惯，以及创建尽可能少或没有空间的站点目录。

还有其他 URL 讨厌的字符被替换为 %#。这是由于百分比编码，并且可以在此 SO 帖子中找到示例和文章。

于 2013-08-22T12:50:13.057 回答