3

是否可以使用 EPPlus 库在 Excel 工作表中创建形状的副本/克隆?

我知道我可以得到一个现有的对象

var shapeExisting = ws.Drawings["ShapeName"];

ws作为 Worksheet 对象)

和一个创造新的形状

var shapeNew = ws.Drawings.AddShape("NewName", eShapeStyle.RtTriangle);

但是,我找不到克隆的方法shapeExisting

4

2 回答 2

1

似乎没有内置功能,所以在找到更好的解决方案之前,我添加了以下方法EPPlus\Drawings\ExcelDrawings.cs

public ExcelShape CloneShape(string SourceName, string TargetName)
{
    if ( _drawingNames.ContainsKey(TargetName.ToLower()))
    {
        throw new Exception("Target name already exists in the drawings collection");
    }

    if (!_drawingNames.ContainsKey(SourceName.ToLower()))
    {
        throw new Exception("Source shape does not exist in the drawings collection");
    }

    ExcelShape shape = new ExcelShape(this, this._drawingsXml,
                               (ExcelShape) this[SourceName]);
    shape.Name = TargetName;
    _drawings.Add(shape);
    _drawingNames.Add(TargetName.ToLower(), _drawings.Count - 1);
    return shape;
}

还有这个构造函数ExcelShape.cs

internal ExcelShape(ExcelDrawings drawings, XmlDocument DrawingsXml, ExcelShape shapeSource) :
            base(drawings, shapeSource._topNode.Clone(), "xdr:sp/xdr:nvSpPr/xdr:cNvPr/@name")

{
     this.init();
     XmlNode colNode = DrawingsXml.SelectSingleNode("//xdr:wsDr", NameSpaceManager);             
     colNode.AppendChild(this._topNode);
}
于 2013-08-22T21:58:18.583 回答
0

我刚刚找到了一个使用当前版本的 EPPlus (5.2.0) 克隆形状的解决方案,我想在这里为任何感兴趣的人发布:

var clonedShape = 
     ws.Drawings.AddShape(
         "NewName",
         ws.Drawings["ShapeName"].As.Shape
     );
于 2020-07-02T12:40:12.457 回答