我正在尝试使用 AJAX 发送和接收参数而没有任何成功
首先,我选择 AREA 而不是该地区的 CITIES。
你能告诉我我做错了什么吗?
客户端:
<script>
$(document).ready(function(){
$("#first").click(
function(){
var area_id=$("#area_id").val();
$.ajax({
type: "POST",
url: "recs.php",
data: "area_id="+area_id,
cache:false,
success:
function(data){
$("#second").html(data.message);
}
});
return false;
});
});
</script>
<form method="post" action="tosomewhere.php">
<select id="first" name="area_id">
<option value="1">1</option>
<option value="2">2</option>
</select>
<select id="second" name="section"> </select>
</form>
服务器端:
$areaID = $_POST['area_id'];
$second_option = "";
$query2 = mysql_query("SELECT * FROM `cities` WHERE area_id = $areaID ORDER BY id ASC");
while($index = mysql_fetch_array($query2))
{
$id = $index['id'];
$name = $index['name'];
$second_option .= "<option value='$id'>$name</option>";
}
echo $second_option;
exit;
谢谢先进
编辑后:
我将代码更改为更简单的代码:
客户端:
<script>
$(document).ready(function(){
$("#first").click(
function(){
var area_id=$("#area_id").val();
$.ajax({
type: "GET",
url: "recs.php",
data: "area_id="+area_id,
cache:false,
success:
function(data){
$("#second").html(data);
}
});
return false;
});
});
</script>
<form method="post" action="tosomewhere.php">
<select id="first" name="area_id">
<option value="1">1</option>
<option value="2">2</option>
</select>
<div id="second"></div>
</form>
服务器端:
some text
我仍然没有将字符串放入