我有一个 List 集合，其中包含 DB 中的经理和员工姓名列表。And I have another list which holds project list in a dropdownlist... When one project is selected then table must be created according to this projecet's emloyees and manager in a table... For example...
从下拉列表中选择的 AndroidApp 项目 然后它应该创建一个表，其中包含像这样的经理和员工的姓名... Html 表... 我尝试使用 jstl 创建，但我做不到。
|manager| Employee|
Susan | John
Susan | Joe
Susan | Megan
我正在使用 Java 平台开发 web-app 项目。我有 Servlet、JSP、DB 来做到这一点。我对列表等进行了编码。我认为此时我的问题是 html 编码或其他可能是什么？我的代码...
相关的 JSP 页面是项目...
<%@page import="com.eteration.leavesystem.model.Person"%>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ page import="java.io.*,java.util.*,java.sql.*"%>
<%@ page import="javax.servlet.http.*,javax.servlet.*"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/sql" prefix="sql"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/fmt" prefix="fmt" %>
<%@ taglib uri="http://java.sun.com/jsp/jstl/functions" prefix="fn" %>
<%@ page session="true" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="">
<select name="projects" multiple>
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="opel">Opel</option>
<option value="audi">Audi</option>
</select> <input type="submit" value="Kaydet">
</form>
<br>
<script
src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">
</script>
<script>
$(function(){
$("#addProject").click(function(){
$(this).next().slideToggle();
});
});
</script>
<button id="addProject">Proje Ekle</button>
<div style="display:none;">
<form action="./UserProjectServlet" method="POST">
<input type="text" name="AddedProject" /><br/>
<button class="hidden">Ekle</button>
</form>
</div>
<form action="./PopulateProjectServlet" method="get">
<select name="selectedProject" id="selectedProject" onchange= "this.form.submit()" >
<c:forEach items="${projects}" var="project">
<option value="${project.code}">${project.desc}"</option>
</c:forEach>
<table border="1" cellpadding="5">
<caption><h2>List of users</h2></caption>
<tr>
<th>Manager</th>
<th>Employees</th>
</tr>
<c:forEach items="${projectTable}" var="projectTable">
<tr>
<td><c:out value="${projectTable.pm.name}" /></td>
<td><c:out value="${projectTable.e.name}" /></td>
</tr>
</c:forEach>
</table>
</select>
</form>
</body>
</html>
我成功地将项目列出到下拉列表并从中获取选定的值 id。然后我做了 onchange 方法来列出有名字的项目信息。
我的结果类列出了项目表信息（名称）
public class ProjectResultTableView {
static mysqlCon con=new mysqlCon();
public static List<ProjectTable> getProjectInfo(String projectId) throws SQLException {
List<ProjectTable> projectTableList = new ArrayList<ProjectTable>();
String query = "SELECT distinct e.name AS employee_name, pm.name AS manager_name FROM project_employee AS pe LEFT OUTER JOIN employee AS e ON e.employee_id = pe.employee_id LEFT OUTER JOIN project AS p ON p.project_id = pe.project_id LEFT OUTER JOIN employee AS pm ON pm.employee_id = p.manager_id WHERE pe.project_id =" +projectId+ " ;";
Statement stmt = con.getConnection().createStatement();
ResultSet rs = stmt.executeQuery(query);
if(rs!=null){
while (rs.next()) {
projectTableList.add(new ProjectTable(rs.getString("pm.name"),rs.getString("e.name")));
}
}
con.getConnection().close();
return projectTableList;
}
}
我的伺服器
@WebServlet("/ProjectResultServlet")
public class ProjectResultServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public ProjectResultServlet() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
try {
String selectedProject = request.getParameter("selectedProject");
List<ProjectTable> projectTable = ProjectResultTableView.getProjectInfo(selectedProject);
request.setAttribute("projectTable", projectTable);
request.getRequestDispatcher("/UserHome/Projects.jsp").forward(request, response);
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
request.getRequestDispatcher("/UserHome/Projects.jsp").forward(request, response);
}
}
所以我认为它与我的 html 代码中的 jstl 或某些东西有关。如果还有更多错误请帮助我.. 我的问题是如何在不提交按钮的情况下根据所选项目创建表格。我想使用 onchange 或类似的东西做同样的事情:) 在此先感谢...