133

我在 MVC 4 中使用 C# 将一些值插入到 SQL 表中。实际上,我想插入值并返回最后插入记录的“ID”。我使用以下代码。

public class MemberBasicData
{
    public int Id { get; set; }
    public string Mem_NA { get; set; }
    public string Mem_Occ { get; set; }     
}

插入时,ID 在数据库中自动递增。

public int CreateNewMember(string Mem_NA, string Mem_Occ )
{
    using (SqlConnection con=new SqlConnection(Config.ConnectionString))
    {
        using(SqlCommand cmd=new SqlCommand("INSERT INTO Mem_Basic(Mem_Na,Mem_Occ) VALUES(@na,@occ)",con))
        {
            cmd.Parameters.AddWithValue("@na", Mem_NA);
            cmd.Parameters.AddWithValue("@occ", Mem_Occ);
            con.Open();

            int modified = cmd.ExecuteNonQuery();

            if (con.State == System.Data.ConnectionState.Open) con.Close();
                return modified;
        }
    }
}
   

我知道ExecuteNonQuery表示影响行的数字。而不是我使用

int modified = (int)cmd.ExecuteScalar();

但它不起作用。请帮我解决这个问题。是否有任何代码cmd.ExecuteInsertAndGetID()(不适用于我的代码)。

4

7 回答 7

246

以下解决方案适用于 sql server 2005 及更高版本。您可以使用输出来获取必填字段。代替 id 你可以写你想要返回的密钥。像这样做

适用于 SQL SERVER 2005 及更高版本

    using(SqlCommand cmd=new SqlCommand("INSERT INTO Mem_Basic(Mem_Na,Mem_Occ) output INSERTED.ID VALUES(@na,@occ)",con))
    {
        cmd.Parameters.AddWithValue("@na", Mem_NA);
        cmd.Parameters.AddWithValue("@occ", Mem_Occ);
        con.Open();

        int modified =(int)cmd.ExecuteScalar();

        if (con.State == System.Data.ConnectionState.Open) 
            con.Close();

        return modified;
    }
}

对于以前的版本

    using(SqlCommand cmd=new SqlCommand("INSERT INTO Mem_Basic(Mem_Na,Mem_Occ)  VALUES(@na,@occ);SELECT SCOPE_IDENTITY();",con))
    {
        cmd.Parameters.AddWithValue("@na", Mem_NA);
        cmd.Parameters.AddWithValue("@occ", Mem_Occ);
        con.Open();

        int modified = Convert.ToInt32(cmd.ExecuteScalar());

        if (con.State == System.Data.ConnectionState.Open) con.Close();
            return modified;
    }
}
于 2013-08-22T06:50:32.927 回答
53

将查询更改为

"INSERT INTO Mem_Basic(Mem_Na,Mem_Occ) VALUES(@na,@occ); SELECT SCOPE_IDENTITY()"

这将返回您可以使用的最后插入的 IDExecuteScalar

于 2013-08-22T06:50:05.400 回答
21

SQL Server 存储过程:

CREATE PROCEDURE [dbo].[INS_MEM_BASIC]
    @na varchar(50),
    @occ varchar(50),
    @New_MEM_BASIC_ID int OUTPUT
AS
BEGIN
    SET NOCOUNT ON;

    INSERT INTO Mem_Basic
    VALUES (@na, @occ)

    SELECT @New_MEM_BASIC_ID = SCOPE_IDENTITY()
END

C#代码:

public int CreateNewMember(string Mem_NA, string Mem_Occ )
{
    // values 0 --> -99 are SQL reserved.
    int new_MEM_BASIC_ID = -1971;   
    SqlConnection SQLconn = new SqlConnection(Config.ConnectionString);
    SqlCommand cmd = new SqlCommand("INS_MEM_BASIC", SQLconn);

    cmd.CommandType = CommandType.StoredProcedure;

    SqlParameter outPutVal = new SqlParameter("@New_MEM_BASIC_ID", SqlDbType.Int);

    outPutVal.Direction = ParameterDirection.Output;
    cmd.Parameters.Add(outPutVal);
    cmd.Parameters.Add("@na", SqlDbType.Int).Value = Mem_NA;
    cmd.Parameters.Add("@occ", SqlDbType.Int).Value = Mem_Occ;

    SQLconn.Open();
    cmd.ExecuteNonQuery();
    SQLconn.Close();

    if (outPutVal.Value != DBNull.Value) new_MEM_BASIC_ID = Convert.ToInt32(outPutVal.Value);
        return new_MEM_BASIC_ID;
}

我希望这些对你有帮助......

如果需要,您也可以使用它...

public int CreateNewMember(string Mem_NA, string Mem_Occ )
{
    using (SqlConnection con=new SqlConnection(Config.ConnectionString))
    {
        int newID;
        var cmd = "INSERT INTO Mem_Basic(Mem_Na,Mem_Occ) VALUES(@na,@occ);SELECT CAST(scope_identity() AS int)";

        using(SqlCommand cmd=new SqlCommand(cmd, con))
        {
            cmd.Parameters.AddWithValue("@na", Mem_NA);
            cmd.Parameters.AddWithValue("@occ", Mem_Occ);

            con.Open();
            newID = (int)insertCommand.ExecuteScalar();

            if (con.State == System.Data.ConnectionState.Open) con.Close();
                return newID;
        }
    }
}
于 2013-08-22T07:50:20.807 回答
1
USE AdventureWorks2012;
GO
IF OBJECT_ID(N't6', N'U') IS NOT NULL 
    DROP TABLE t6;
GO
IF OBJECT_ID(N't7', N'U') IS NOT NULL 
    DROP TABLE t7;
GO
CREATE TABLE t6(id int IDENTITY);
CREATE TABLE t7(id int IDENTITY(100,1));
GO
CREATE TRIGGER t6ins ON t6 FOR INSERT 
AS
BEGIN
   INSERT t7 DEFAULT VALUES
END;
GO
--End of trigger definition

SELECT id FROM t6;
--IDs empty.

SELECT id FROM t7;
--ID is empty.

--Do the following in Session 1
INSERT t6 DEFAULT VALUES;
SELECT @@IDENTITY;
/*Returns the value 100. This was inserted by the trigger.*/

SELECT SCOPE_IDENTITY();
/* Returns the value 1. This was inserted by the 
INSERT statement two statements before this query.*/

SELECT IDENT_CURRENT('t7');
/* Returns value inserted into t7, that is in the trigger.*/

SELECT IDENT_CURRENT('t6');
/* Returns value inserted into t6. This was the INSERT statement four statements before this query.*/

-- Do the following in Session 2.
SELECT @@IDENTITY;
/* Returns NULL because there has been no INSERT action 
up to this point in this session.*/

SELECT SCOPE_IDENTITY();
/* Returns NULL because there has been no INSERT action 
up to this point in this scope in this session.*/

SELECT IDENT_CURRENT('t7');
/* Returns the last value inserted into t7.*/
于 2013-08-22T06:52:50.693 回答
0

如果您使用 EF:

 Class Person{
 public int Id {get;set;}
 public string Name {get;set;}
}

您设置名称值:

 Person p = new Person(){
  Name = "James"
};
DbContext.Persons.Add(p);
DbContext.SaveChanges();

//p.Id = new Id from database
//p.Name = James

您只需保存它,您将从数据库中获取 Id。

于 2021-11-02T08:15:58.593 回答
0
SELECT SCOPE_IDENTITY() AS 'Identity'

这将返回仅在当前范围内插入的标识值

SELECT @@IDENTITY AS 'Identity'; 

this 不限于特定范围因此这将返回标识列的最新值,并且不一定是来自同一范围的标识值。

于 2021-05-19T06:42:36.267 回答
-2
using(SqlCommand cmd=new SqlCommand("INSERT INTO Mem_Basic(Mem_Na,Mem_Occ) " +
    "VALUES(@na,@occ);SELECT SCOPE_IDENTITY();",con))
{
    cmd.Parameters.AddWithValue("@na", Mem_NA);
    cmd.Parameters.AddWithValue("@occ", Mem_Occ);
    con.Open();

    int modified = cmd.ExecuteNonQuery();

    if (con.State == System.Data.ConnectionState.Open) con.Close();
        return modified;
}

SCOPE_IDENTITY:返回插入到同一范围内的标识列中的最后一个标识值。更多详情http://technet.microsoft.com/en-us/library/ms190315.aspx

于 2013-08-22T07:01:47.493 回答