2

我最近了解到 mysql_* 已被贬值，我有一个关于如何重写某些东西的快速问题。

$db = mysql_connect("localhost","root","PASSWORD");
if(!$db) die("Error connecting to MySQL database.");
mysql_select_db("FormData" ,$db);

我试过这样重写它...... 

$mysqli = new mysqli("localhost", "root", "PASSWORD", "FormData", $db);
if(!$db) die("Error connecting to MySQL database.");

但是当它发布我的表单时，我得到“连接到 MySQL 数据库时出错”。错误。我可以通过使用它来修复它，但我想知道如何添加错误连接。

$mysqli = new mysqli("localhost", "root", "PASSWORD", "FormData");

当我尝试学习所有新的 MySQLi 东西时，任何帮助都会很棒！

4

4 回答 4

3

PHP网站

直接来自 php.net

<?php
$mysqli = new mysqli('localhost', 'fake_user', 'my_password', 'my_db');

// Works as of PHP 5.2.9 and 5.3.0.
if ($mysqli->connect_error) {
    die('Connect Error: ' . $mysqli->connect_error);
}
?>

编辑：

下面的内容也将允许您按照自己的方式进行操作。

$mysqli = mysqli_connect('localhost', 'fake_user', 'my_password', 'my_db');

那么你就可以：

if (!$mysqli) {
   //handle the error
}

如果可能，考虑 PDO。他们和我很相似。

于 2013-08-21T20:43:26.020 回答
2 
$mysqli = new mysqli("localhost", "root", "PASSWORD", "FormData", $db);
if(!$db) die("Error connecting to MySQL database.");

应该

$mysqli = new mysqli("localhost", "root", "PASSWORD", "FormData");
if($mysqli->connect_error) die("Error connecting to MySQL database.");

mysqli() 的参数是：

[ string $host = ini_get("mysqli.default_host") [, string $username = ini_get("mysqli.default_user") [, string $passwd = ini_get("mysqli.default_pw") [, string $dbname = "" [, int $port = ini_get("mysqli.default_port") [, string $socket = ini_get("mysqli.default_socket") ]]]]]]

不知道为什么你试图使用$db变量来设置连接的端口，然后检查端口变量是否为真......

为了将来参考，最好先看看文档

编辑

正如@Touch 指出的那样，您必须检查是否存在错误，而不仅仅是该对象存在。编辑代码以反映这一点。

于 2013-08-21T20:43:35.363 回答
0

使用 mysqli：

define('DB_HOST', 'localhost');
define('DB_NAME', 'some_database_name');
define('DB_USER', 'some_user');
define('DB_PASS', 'some_password');


$Connection = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
if (!$Connection->connect_errno) 
{
  //do your prepared stuffs
}
else
{
  die("Database Connection error:".$Connection->connect_error);
}

或使用 PDO

try 
{
  $PDOConnection = new PDO('mysql:host='.DB_HOST.';dbname='.DB_NAME.'', DB_USER, DB_PASS);
  $PDOConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

  //do your prepared stuffs

  $PDOConnection = null;
} 
catch(PDOException $e) 
{
  die('ERROR: ' . $e->getMessage());
}
于 2013-08-21T21:02:01.723 回答
0

我编写了一个名为better_mysqli的类，它扩展了 mysqli 使其更易于使用。

以下示例显示了您的问题的答案，还显示了 better_mysqli 类的基本用法。您可以在此处查看带有大量注释的详细示例：better_mysqli 的详细用法 

<?php

  include_once('better_mysqli.php');  // can be obtained from: http://pastebin.com/ATyzLUfK

  // THIS NEXT PART ANSWERS YOUR QUESTION 
  // THIS NEXT PART ANSWERS YOUR QUESTION 
  // THIS NEXT PART ANSWERS YOUR QUESTION 

  // THE ONLY DIFFERENCE IN THE CONNECTION WHEN USING better_mysqli AND mysqli
  // is $mysqli = new better_mysqli(...)  and $mysqli = new mysqli(...) 

  // == Instantiate the mysqli database object (aka open the database) ==
  $mysqli = new better_mysqli('your_server', 'your_user', 'your_pass', 'your_db_name');
  if (mysqli_connect_errno()) {
     error_log(sprintf("Can't connect to MySQL Server. Errorcode: %s\n", mysqli_connect_error()));
     exit;
  }


  // == select example ==
  unless( $sth = $mysqli->select('select * from table1 where col1=? and col2=?', $row, array('col1_placeholder_value', 'col2_placeholder_value'), $debug_level=0, $verbose_debug_output)){
        if($debug_level>0){ echo $verbose_debug_output;}
        // .. do your error handling here
  }
  while($sth->fetch()){
          echo $row['col1'] .', '. $row['col2'] .', and '. $row['col_etc'] .' are accessed like that.<br>';
  }


  // == insert example ==
  $statement = "insert into table1 (col1, col2, date_col, col_etc) values (?, ?, NOW(), ?)";
  unless( $mysqli->insert($statement, array('col1_insert_value', 'col2_insert_value', 'col_etc_value'), $debug_level=0, $verbose_debug_output, $id_of_new_record) ){     
          if($debug_level>0){ echo $verbose_debug_output;}
          // .. do your error handling here
  }


  // == update example ==
  unless($mysqli->update("update table1 set col1=? where col2=?", array('col1_value', 'col2_value'), $debug_level=0, $verbose_debug_output) ){
          if($debug_level>0){ echo $verbose_debug_output;}
          // .. do your error handling here      
  }


  // == delete example ==
  unless( $mysqli->delete("delete from table1 where col1=? where col2=?", array('col1_value', 'col2_value'), $debug_level=0, $verbose_debug_output) ){
          if($debug_level>0){ echo $verbose_debug_output;}
          // .. do your error handling here      
  }


  // in all cases statements are prepared just once and cached so if you reuse any statement the already prepared statement handle is automatically used


?>
于 2013-08-21T21:03:26.560 回答