python - logger.setLevel doesn't return desired level

Question

I'm trying to use this code in my app:

 def logger(log_file='base.log', set_level='INFO', identity='base'):
     set_level = get_settings().logging_setLevel
     if log_file:
         log_path = os.path.join(os.path.expanduser('~'), '/mnt/logs/')
         if not os.path.exists(log_path):
             os.makedirs(log_path)
         handler = logging.FileHandler(log_path+log_file)
     else:
         handler = logging.StreamHandler()

     formatter = logging.Formatter('%(asctime)s - %(name)s - '+ identity +' - %(levelname)s - %(message)s', '%Y-%m-%dT%H:%M:%SZ')
     handler.setFormatter(formatter)
     logger = logging.getLogger(identity)
     logger.addHandler(handler)
     logger.setLevel(eval("logging." + set_level))

     return logger

But the problem is regardless what level I choose in set_level argument it still produces all levels ('DEBUG' and so on....).

Can you please help me identify the problem.

Answer 1

而不是使用eval，试试这个：

level = logging.getLevelName(set_level)
logger.setLevel(level)