0

我试图将我点击/选择的图像发送到新活动这是我的代码

public int getCount() {
    return mThumbIds.length;
}
public View getView(final int position, View convertView, ViewGroup parent) {
        ImageView imageView; 
        if (convertView == null) {  // if it's not recycled, initialize some attributes
            imageView = new ImageView(mContext);
            imageView.setLayoutParams(new GridView.LayoutParams(85, 85));
            imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
            imageView.setPadding(8, 8, 8, 8);
            imageView.setOnClickListener(new OnClickListener() {

                @Override
                public void onClick(View v) {
                    // TODO Auto-generated method stub
                    Intent intent = new Intent(mContext,HeroData.class);
                    intent.putExtra("imageID", position);
                    mContext.startActivity(intent);
                }
            });
        } else {
            imageView = (ImageView) convertView;
        }

        imageView.setImageResource(mThumbIds[position]);
        return imageView;

    }

private Integer[] mThumbIds = {
        R.drawable.pic1, R.drawable.pic12,
        R.drawable.pic2, R.drawable.pic13,
        R.drawable.pic3, R.drawable.pic14,

};

}

并尝试在新活动中接收它

Bundle bdl = getIntent().getExtras();
    int index = bdl.getInt("imageID");
    ImageView image = (ImageView) findViewById(R.id.imageview);
    image.setImageResource();//the problem ! how to receive the selected image

我想知道我正在发送（“imageID”，位置）；如何获取选定的图像

4

3 回答 3

2

由于您正在发送资源，因此您可以发送资源 id 而不是它在数组中的索引。像这样的东西：

intent.putExtra("imageID", mThumbIds[position]);
mContext.startActivity(intent);

在您的活动中：

Bundle bdl = getIntent().getExtras();
int imageRes = bdl.getInt("imageID");
ImageView image = (ImageView) findViewById(R.id.imageview);
image.setImageResource(imageRes);

希望有帮助。

于 2013-08-21T12:23:48.400 回答
1

像这样使用...

gridView.setOnItemClickListener(new OnItemClickListener()   
    {

        public void onItemClick(AdapterView<?> parent, View v,int position, long id) 

        {

            Intent i = new Intent(getApplicationContext(), HeroData.class);



            i.putExtra("imageID", position);

             startActivity(i);


        }
    });

需要右键单击gridview ...

于 2013-08-21T12:23:58.160 回答
0

您可以将可绘制资源保存在另一个地方，例如，您可以在资源中进行，如字符串数组

<resources>

<string-array name="thumbs_imgs">
    <item>@drawable/pic1</item>
    <item>@drawable/pic2</item>
    <item>@drawable/pic3</item>
</string-array>

</resources>

然后通过 index drawable 获取您需要的内容

TypedArray imgs = getResources().obtainTypedArray(R.array.thumbs_imgs);
//get resourceid by index
mImgView1.setImageResource(imgs.getResourceId(i, -1));
于 2013-08-21T12:24:50.220 回答