0

我有列表视图,每个项目都包含一个文本视图和一个无线电组。Radiogroup 包含两个单选按钮。我的问题是,当我滚动列表视图时,多个联系人被选中(即在列表视图的不可见区域中的相同位置出现的联系人被选中)那么我应该如何克服这个问题,请帮助我?

xml file : 
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="horizontal" >

    <TextView
        android:id="@+id/tv_number"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:textAppearance="?android:attr/textAppearanceMedium" />

    <RadioGroup  android:id="@+id/selection"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:orientation="horizontal" >

        <RadioButton
            android:id="@+id/allow"
            android:paddingRight="15dp"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content" />

        <RadioButton
            android:id="@+id/block"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content" />
    </RadioGroup>

</RelativeLayout>

Adapter code : 


                @Override
        public View getView(final int position, View convertView, ViewGroup parent) {

            final ViewHolder holder;
             if (convertView == null) {
             convertView = getLayoutInflater().inflate(R.layout.lv_contact, null);

             holder = new ViewHolder();
             convertView.setTag(holder);
             holder.rbg = (RadioGroup) convertView.findViewById(R.id.selection);
             holder.rbg.setTag(position);

             holder.rbAllow = (RadioButton) convertView.findViewById(R.id.allow);
             holder.rbBlock = (RadioButton) convertView.findViewById(R.id.block);
             holder.tv_contactNumber = (TextView) convertView.findViewById(R.id.tv_number);
             holder.rbg.setOnCheckedChangeListener(new OnCheckedChangeListener() {

             @Override
             public void onCheckedChanged(RadioGroup group, int checkedId) {
             Contact contact;
             switch (checkedId) {
             case R.id.allow:

             contact = contactList.get(position);
             contact.setAllow(true);

             break;

             case R.id.block:

             contact = contactList.get(position);
             contact.setAllow(false);

             break;
             default:
             break;
             }

             });

             } else {
             holder = (ViewHolder)convertView.getTag();
             convertView.setTag(holder);
             }

             Contact con = contactList.get(position);
             holder.tv_contactNumber.setText(con.getNumber());  

            if (!con.isAllow() && !con.isBlock()) {

            } else {

                if (con.isAllow()) {
                    holder.rbAllow.setChecked(true);
                    holder.rbBlock.setChecked(false);
                } else {
                    holder.rbAllow.setChecked(false);
                    holder.rbBlock.setChecked(true);
                }
            }
                 return convertView;
        }



Contact file : 
public class Contact {

    private String number;

    private boolean Allow;
    private boolean Block;

    public boolean isAllow() {
        return Allow;
    }

    public void setAllow(boolean isAllow) {
        Allow = Allow;
    }

    public boolean isBlock() {
        return Block;
    }

    public void setBlock(boolean isBlock) {
            Block = isBlock;
    }


    public String getName() {
        return name;
    }

    public String getNumber() {
        return number;
    }

    public Contact(String number, boolean allow, boolean block) {
        name = name;
        Allow = allow;
        Block = block;
    }   

}
4

1 回答 1

0

这是设计使然,因为列表视图中的视图被回收以降低内存消耗。解决此问题的一种方法是创建一个布尔数组,其中包含提供给列表视图的数据长度,并在复选框上创建一个侦听器,该侦听器在单击时将布尔数组中的该位置设置为真或假。然后在声明侦听器之前的适配器中,只需使用存储在数组索引中的值初始化每个复选框。

于 2013-08-22T07:23:58.407 回答