2

我在 sql 2012 中有两个表:名称和产品结构:

名称id int increment, name1 nvarchar(50)

产品id int increment, products nvarchar(50), id_name int

表的值为:

名称表:

Id   name1
1    pop
2    andi

产品表:

Id   products   id_name
1    coke       1
2    pizza      1
3    orange     2

我已经完成了这个查询:

select name.name1, prod.product, prod.id_name
from name
join prod on name.id=prod.id_name

我怎样才能得到这个结果:

pop ->coke, pizza
andi->orange  
4

3 回答 3

5

不幸的是,在 SQL Server 中没有简单的方法可以做到这一点。已知的解决方案是:

  • xml 技巧(见下文);
  • 使用变量来累积数据(不适用于多组行,仅使用游标);
  • 自定义 CLR 聚合;

这是xml:

select
    n.name1,
    stuff(
        (
         select ', ' + p.product
         from prod as p
         where p.id_name = n.id
         for xml path(''),  type).value('.', 'nvarchar(max)')
    , 1, 2, '') as products
from name as n

sql fiddle demo

这是变量:

declare @product nvarchar(max), @id int

select @id = 1

select @product = isnull(@product + ', ', '') + product
from prod
where id_name = @id

select name1, @product as products
from name 
where id = @id

sql fiddle demo

于 2013-08-20T12:39:57.663 回答
3

sqlfiddle

select
n.nameid [id],
n.name [name],
count(*)[count],
    stuff(
        (
         select ', ' + p.prod
         from prodtbl as p
         where p.nameid = n.nameid
         for xml path(''),  type).value('.', 'nvarchar(max)'), 1, 1, '') as products
from nametbl n, prodtbl p
where p.nameid = n.nameid
group by n.nameid, n.name
order by [id];

在此处输入图像描述

于 2013-08-20T13:22:19.133 回答
3

尝试这个:

SELECT
G.id,
G.name1,
stuff(
    (select cast(',' as varchar(10)) + U.product
    from prod U
    WHERE U.id_name = G.id
    order by U.product
    for xml path('')
), 1, 1, '') AS prod
FROM name G
ORDER BY G.name1 ASC
于 2013-08-20T12:43:41.110 回答