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我正在尝试使用 PDO 准备语句运行查询，该语句允许我让用户选择一个字段，然后为该字段输入值，并将其包含在我的查询中。

所以在这个基本查询中：

$sql = "SELECT LastName, FirstName FROM administrators WHERE Status=:Status "; 
$stmt->bindParam(':Status',$Status, PDO::PARAM_STR);

效果很好。

但我有一个搜索表单，允许说用户选择显示名字、姓氏的下拉菜单，然后是一个文本框来输入搜索词

$sql = "SELECT LastName, FirstName FROM administrators WHERE Status=:Status **AND FIELD = TERM**";

到目前为止，我还没有在网上找到任何好的例子。任何指导表示赞赏。

我在用：

$params = array();
    if (!empty($SearchField) && !empty($SearchFor)) 
    {
        $params['SearchField'] = $SearchField;
        $params['SearchFor'] = $SearchFor;
    }

但我收到错误：致命错误：未捕获的异常 'PDOException' 带有消息'SQLSTATE [42S22]：找不到列：'where 子句'中的 1054 未知列 'SearchField''

更新代码：

这是我在表单中使用的代码：

 <input id="searchtext" name="searchtext" type="text" placeholder="Search" value="<?php echo GetParam('searchtext'); ?>" />   
                            <select name="searchby">
                                <option value="">Search By</option>
                                <option id="LastName" value="LastName" <?php if(GetParam('searchby') == 'LastName'){echo "selected='selected'";}?>>Last Name</option>
                                <option id="FirstName" value="FirstName" <?php if(GetParam('searchby') == 'FirstName'){echo "selected='selected'";}?>>First Name</option>
                                <option id="RoleName" value="RoleName" <?php if(GetParam('searchby') == 'RoleName'){echo "selected='selected'";}?>>Role Name</option>
                            </select>
                            <input type="submit" id="submit" name="command" value="search" />

这是我的方法的代码：

public function GetAllUsers($Status = 'A',$SearchField = '',$SearchFor = '')
{
$db=DB::getInstance();
$sql = "SELECT administrators.AdminId, AdminEmail, LastName, FirstName, PrimaryPhone, CellPhone, administrators.Status, LoginDateTime, RoleName FROM administrators INNER JOIN permissions on permissions.AdminId=administrators.AdminId INNER JOIN roles on roles.RoleId=permissions.RoleId INNER JOIN sessions on sessions.AdminId=administrators.AdminId WHERE Status=:Status ";

$stmt=$db->prepare($sql);
$stmt->bindParam(':Status',$Status, PDO::PARAM_STR);

$stmt->execute();
return $stmt->fetchAll(PDO::FETCH_OBJ);
}
4

1 回答 1

0

您不能将参数用于标识符（表/列名等）。您需要适当地清理这些并将它们注入到您的查询字符串中。您仍然可以为该值使用参数。我可能还会选择一组可搜索的列。例如

// create a map of field key to column name mappings
$searchCols = array(
    'fn' => 'FirstName',
    'ln' => 'LastName'
);

显示表单时，您可以使用它来生成选项

<select name="SearchField">
    <?php foreach ($searchCols as $key => $label) : ?>
    <option value="<?= htmlspecialchars($key) ?>"><?= htmlspecialchars($label) ?></option>
    <?php endforeach ?>
</select>

现在使用它来构建您的查询

// you'll probably want some more validation around this
$searchField = $searchCols[$_POST['SearchField']];

$query = sprintf('SELECT LastName, FirstName FROM administrators WHERE Status = :Status AND `%s` = :searchTerm',
    $searchField);

// prepare statement and bind status, etc ...

$stmt->bindParam(':searchTerm', $SearchFor);
于 2013-08-20T01:19:58.243 回答