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我有一个要转换为树结构的列表。如何将其转换为树结构？

我已经通过递归检查父子关系 C#线程来查看构建树类型列表，但是由于我的类中的键是字符串，所以我不能使用该解决方案。请帮忙

internal class Program
{
        private static void Main(string[] args)
        {
            List<node> nodeList = new List<node>();
            node n = new node("A", "A1", null, 1); nodeList.Add(n);
            n = new node("B", "A2", "A1", 2); nodeList.Add(n);
            n = new node("C", "A3", "A1", 2); nodeList.Add(n);
            n = new node("D", "A4", "A1", 2); nodeList.Add(n);

            n = new node("E", "A5", "A2", 3); nodeList.Add(n);
            n = new node("F", "A6", "A5", 4); nodeList.Add(n);
            n = new node("G", "A7", "A3", 3); nodeList.Add(n);
            n = new node("H", "A8", "A4", 3); nodeList.Add(n);
            n = new node("I", "A9", "A4", 3); nodeList.Add(n);
            n = new node("J", "A10", "A4", 3); nodeList.Add(n);
            n = new node("K", "A11", "A10", 4); nodeList.Add(n);
            n = new node("L", "A12", "A10", 4); nodeList.Add(n);
            n = new node("M", "A13", "A12", 5); nodeList.Add(n);
            n = new node("N", "A14", "A12", 5); nodeList.Add(n);
            n = new node("O", "A15", "A10", 4); nodeList.Add(n);

            n = new node("P", "A16", null, 1); nodeList.Add(n);
            n = new node("Q", "A17", "A16", 2); nodeList.Add(n);
        }
}

public class node
{
        public string name { get; set; }
        public string key { get; set; }
        public string parentKey { get; set; } 
        public int level { get; set; }

        public List<node> Children { get; set; }

        public node(string Name, string Key, string PK, int Level)
        {
            name = Name;
            key = Key;
            parentKey = PK;
            level = Level;
        }
}
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1 回答 1

1

将父 ID 从更改为非常简单的int重构string

public static class GroupEnumerable {

    public static IList<node> BuildTree(this IEnumerable<node> source)
    {
        var groups = source.GroupBy(i => i.parentKey);

        var roots = groups.FirstOrDefault(g => g.Key==null).ToList();

        if (roots.Count > 0)
        {
            var dict = groups.Where(g => g.Key!=null).ToDictionary(g => g.Key, g => g.ToList());
            for (int i = 0; i < roots.Count; i++)
                AddChildren(roots[i], dict);
        }

        return roots;
    }

    private static void AddChildren(node node, IDictionary<string, List<node>> source)
    {
        if (source.ContainsKey(node.key))
        {
            node.Children = source[node.key];
            for (int i = 0; i < node.Children.Count; i++)
                AddChildren(node.Children[i], source);
        }
        else
        {
            node.Children = new List<node>();
        }
    } 
}
于 2013-08-19T15:08:15.023 回答