我创建了一个 upload_video.php 页面并遇到了问题。希望一些 PHP 天才愤怒:可以帮助我一点,我会非常感激。
更改我的视频页面不显示视频缩略图。链接到 include/generatevideothumb.php
在我的 upload_video.php 页面中,我定义了 thumb 变量如下
// Thumb size
$th_max_height1 = 150;
$th_max_width1 = 250;
$th_max_width = 55;
$th_max_height = 55;
$thumb_dir="upload/video/thumbs/";
$thumb_dir1="upload/video/thumbs1/";
// Thumb
$thumb_video_name=$video_name;
generatevideothumb($dir,$th_max_width, $th_max_height,$thumb_dir,$thumb_video_name);
generatevideothumb($dir,$th_max_width1, $th_max_height1,$thumb_dir1,$thumb_video_name);
问题在于创建视频缩略图。错误是:警告:imagecreate() [function.imagecreate]:第 25 行的 html\include\generatevideothumb.php 中的图像尺寸无效
下面的 generatevideothumb.php 的完整代码
<?php
function generatevideothumb($im_file,$th_max_width, $th_max_height,$thumb_dir,$thumb_video_name)
{
@chmod($im_file,0777);
$image_attribs = getimagesize($im_file);
if($image_attribs[0]>$th_max_width)
{
$ratio = $th_max_width/$image_attribs[0];
$th_width = $image_attribs[0] * $ratio;
$th_height = $image_attribs[1] * $ratio;
}
elseif($image_attribs[1]>$th_max_height)
{
$ratio = $th_max_height/$image_attribs[1];
$th_width = $image_attribs[0] * $ratio;
$th_height = $image_attribs[1] * $ratio;
}
else
{
$th_width = $image_attribs[0];
$th_height = $image_attribs[1];
}
**//This code below is where I get that error saying invalid image dimensions
$im_new = imagecreate($th_width,$th_height); //returns an image identifier representing a black image of size x_size by y_size.
$th_file_name = $thumb_dir.$thumb_video_name;
@chmod($th_file_name,0777);**
if($image_attribs[2]==2)
{
$im_old = imageCreateFromJpeg($im_file);
imagecopyresized($im_new,$im_old,0,0,0,0,$th_width,$th_height, $image_attribs[0], $image_attribs[1]);
imagejpeg($im_new,$th_file_name,100);
}
elseif($image_attribs[2]==1)
{
$im_old = imagecreatefromgif($im_file);
imageCopyResampled($im_new,$im_old,0,0,0,0,$th_width,$th_height, $image_attribs[0], $image_attribs[1]);
imagegif($im_new,$th_file_name,100);
}
}
?>