0

我有这个代码可以完美地显示项目，但是弹出一个错误，我必须点击“确定”查看页面

我已经在网上搜索过，据我了解，这与标题表的列比数据本身多有关，我试图解决这个问题，但由于我是新手（菜鸟），所以一无所获：/

如果有人能对此有所了解，那就太好了！:)

错误

DataTables warning (table id = 'example'): Requested unknown parameter '0' 
from the data source for row 0

我的代码

<?php
//include database connection
include 'db_connect.php';

//query all records from the database
$query = "select * from repair_jobs";

//execute the query
$result = $mysqli->query( $query );

//get number of rows returned
$num_results = $result->num_rows;

//this will link us to our add.php to create new record
if( $num_results > 0){ //it means there's already a database record

    //start table
    //creating our table heading
    echo "<table id='example' cellpadding='0' cellspacing='0' border='0' class='display' >";
    echo "<thead><tr>";
        echo "<th>Client</th>";
        echo "<th>Type</th>";
        echo "<th>Labour</th>";
        echo "<th>ourcosts</th>";
    echo "</thead></tr><tbody><tr class=\"gradeX\">";

    //loop to show each records
    while( $row = $result->fetch_assoc() ){
            //extract row
            //this will make $row['firstname'] to
            //just $firstname only
            extract($row);

            //creating new table row per record
            echo "<tr>";
                echo "<td>{$client}</td>";
                echo "<td>{$type}</td>";
                echo "<td>{$labour}</td>";
                echo "<td>{$ourcosts}</td>";
                                echo "</td>";
            echo "</tr>";
    }

    echo "</table>";//end table

}else{
    //if database table is empty
    echo "No records found.";
}

//disconnect from database
$result->free();
$mysqli->close();

?>

它显示正常，但这个错误让我感到困惑。

4

0 回答 0