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如果服务器套接字中生成的 rand 数小于 4，我的客户端套接字将暂停接收数据。我需要设置超时机制以允许客户端套接字检测到“超时”，然后它将继续发送消息。在我运行服务器套接字然后运行客户端套接字后，错误消息显示如下：

Traceback (most recent call last):
File "E:\Studying\Python workspace\Client\src\Client.py", line 34, in <module>
data , addr = client.recvfrom(1024)
socket.timeout: timed out

服务器套接字：

import random
from socket import *
serverSocket = socket(AF_INET , SOCK_DGRAM)
serverSocket.bind(('', 15000))

while True:

rand = random.randint(0, 10)
message , address = serverSocket.recvfrom (1024)
message = message.upper()
print("received message: ", message)
print("echo to address: ", address)
print(rand)

if rand < 4:
    continue
print("Sending message: ", message)
serverSocket.sendto(message, address)

客户端套接字

import socket

UDP_IP = "127.0.0.1"
RPORT = 15000
MESSAGE = "ping"

print("UDP target IP: ", UDP_IP)
print("UDP target port: ", RPORT)
print("message going to send: ", MESSAGE)

client = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)

i=1

while True:
  try:

    if(i<11): 
        client.sendto(MESSAGE.encode('utf_8'),(UDP_IP, RPORT))
        print("sending message: ", MESSAGE)
        print(i)
        i=i+1
        client.settimeout(2)

        data , addr = client.recvfrom(1024)
        print("received echo: ", data)
        print("received at: " , addr )

  finally:
    print("closing socket")
    client.close()
4

1 回答 1

4

好吧， settimeout() 会产生异常。尝试这个：

while True:
  try:
    if(i<11): 
        client.sendto(MESSAGE.encode('utf_8'),(UDP_IP, RPORT))
        print("sending message: ", MESSAGE)
        print(i)
        i=i+1
        client.settimeout(2)

        data , addr = client.recvfrom(1024)
        print("received echo: ", data)
        print("received at: " , addr )

  except socket.timeout:
    print("closing socket")
    client.close()

如果您想了解有关 socket.settimeout() 的更多信息，请查看此链接： http ://docs.python.org/2/library/socket.html#socket.timeout

希望有帮助！

于 2013-12-20T09:53:10.280 回答