2

我目前有下面的代码。“ins”目前只能有七个值，因此代码就足够了，但是到下个月我被告知将有超过 900 个值！

我假设我可以使用某种数组，而不是编写另外 900 个案例语句。任何人都可以在正确的方向上轻推我吗？

Private Sub test()
Dim i As Long
Dim lr As Long
Dim ins As String

lr = Range("A" & Rows.Count).End(xlUp).Row

For i = 6 To lr
Select Case Cells(i, 20)
    Case Is = "" 
        ins = Mid(Cells(i, 11), 14, 2)
            Select Case Cells(i, 10)
                Case "Inx", "ComInx"
                     Select Case Cells(i, 9)
                         Case "EINX"
                              Select Case ins
                                  Case "LD"
                                      Cells(i, 9).Value = "SR"
                                  Case "GP"
                                      Cells(i, 9).Value = "GAMA"
                                  Case "AV"
                                      Cells(i, 9).Value = "NU"
                                  Case "AX"
                                      Cells(i, 9).Value = "AXC"
                                  Case "MZ"
                                      Cells(i, 9).Value = "MZE"
                                  Case "AD"
                                      Cells(i, 9).Value = "AGD"
                                  Case "AG"
                                      Cells(i, 9).Value = "AG"
                              End Select
                     End Select
            End Select
End Select
Next

End Sub
4

1 回答 1

5

我会为此使用字典对象。这是基于您的线路的概念验证：

Private Sub test()
    Dim i As Long
    Dim lr As Long
    Dim ins As String        
    Dim rngCases As Range, rngCases2 As Range, rngCase As Range
    Dim dicCases As Dictionary

    lr = Range("A" & Rows.Count).End(xlUp).Row

    ' rngCases stores the possible values of ins
    ' Here I assume they are stored in col 40
    Set rngCases = Range(Cells(6, 40), Cells(lr, 40))

    ' rngCases2 stores the values you want to map for each value of ins.
    ' Here I assume they are stored in col 41
    ' No of entries = No of entries of rngCases
    Set rngCases2 = Range(Cells(6, 41), Cells(lr, 41))
    Set dicCases = New Dictionary

    For Each rngCase In rngCases
        If Not dicCases.Exists(rngCase.Value) Then
            dicCases.Add Key:=rngCase.Value, Item:=rngCases2.Value
        End If
    Next rngCase

    For i = 6 To lr
    Select Case Cells(i, 20)
        Case Is = ""
            ins = Mid(Cells(i, 11), 14, 2)
                Select Case Cells(i, 10)
                    Case "Inx", "ComInx"
                         Select Case Cells(i, 9)
                             Case "EINX"
                                ' We simply need to refer to the mapped value of ins
                                 If dicCases.Exists(ins) then
                                     Cells(i, 9) = dicCases.Item(ins)
                                 Else
                                     ' Throw an error or do something here
                                 End If
                         End Select
                End Select
    End Select
    Next

End Sub

要启用Dictionary，请转到Tools->References并选择Microsoft Scripting Runtime。

我希望这能让你开始！

于 2013-08-19T10:38:41.780 回答