1

我一直在研究这个脚本以获得两个日期之间的差异。但是时间会弄乱脚本（http://jsfiddle.net/HuGvd/）。

当脚本在同一天进入新月份时，脚本将停止正常工作。我也尝试在这个脚本中添加分钟，但没有运气真的需要这个家伙的帮助。

function getDateDiff(timestamp) {
if (null === timestamp || timestamp === "" || timestamp === "undefined") return "?";
var splitDate = ((timestamp.toString().split('T'))[0]).split('-');
var splitTime = ((timestamp.toString().split('T'))[1]).split(':');
var d1 = new Date();
var d1Y = d1.getFullYear();
var d2Y = parseInt(splitDate[0], 10);
var d1M = d1.getMonth() + 1;
var d2M = parseInt(splitDate[1], 10);
var d1D = d1.getDate();
var d2D = parseInt(splitDate[2], 10);
var d1H = d1.getHours();
var d2H = parseInt(splitTime[0], 10);
var diffInHours = (d1H + 24 * d1D + 30) - (d2H + 24 * d2D + 30);
if (diffInHours < 24) return diffInHours + " hour";
var diffInDays = (d1D + 30 * d1M + 12) - (d2D + 30 * d2M + 12);
if (diffInDays < 7) return diffInDays + " days";
else if (diffInDays >= 7 && diffInDays < 14) return "1 week";
else if (diffInDays >= 14 && diffInDays < 30) return Math.floor(diffInDays / 7) + " weeks";
var diffInMonths = (d1M + 12 * d1Y) - (d2M + 12 * d2Y);
if (diffInMonths <= 1) return "1 month";
else if (diffInMonths < 12) return diffInMonths + " months";
var diffInYears = Math.floor(diffInMonths / 12);
if (diffInYears <= 1) return "1 year";
else if (diffInYears < 12) return diffInYears + " years";
}
4

2 回答 2

1

日期/时间功能非常复杂，边缘情况比您可能涵盖的要多……不要推出自己的解决方案，使用内置功能。您可以在 javascript 中找到两个日期之间的毫秒数，如下所示：

var now = new Date();
var then = new Date(timestamp);

var diffMS = now - then;

从那里开始，根据您想要的显示方式转换为您想要的任何单位并不难。

http://jsfiddle.net/AMDXq/

作为旁注，这是一个相当普遍的问题。我没看过，但我确定有一个插件或库可以解决这个问题。

于 2013-08-18T22:35:26.013 回答
0

这是查找两个日期之间差异的解决方案。策略是将字符串转换为日期对象，然后计算差值并返回年、月、日等值的数组。

我为“精确”添加了一个参数，因此默认情况下它返回一个整天的值（例如 2013-08-13T23:59:59Z 到 2013-08-14T00:00:01Z 是一天）或精确（其中上述差异为 2 秒）。

// Expects start date to be before end date
// Default is to deal in whole days. For precise differences 
// (hours, minutes and seconds), set precise to true
function dateDifference(start, end, precise) {
  var timeDiff, years, months, days, hours, minutes, seconds;

  // Copy date objects so don't modify originals
  var s = new Date(+start);
  var e = new Date(+end);
console.log(s, e);
  // If not precise, set h,m,s to zero
  if (!precise) {
    s.setUTCHours(0,0,0,0);
    e.setUTCHours(0,0,0,0);
console.log(s, e);
  }

  // Get estimate of year difference
  years = e.getUTCFullYear() - s.getUTCFullYear();

  // Add difference to start, if greater than end, remove one year
  // Note start from restored start date as adding and subtracting years
  // may not be symetric
  s.setFullYear(s.getUTCFullYear() + years);
  if (s > e) {
    --years;
    s = new Date(+start);
    s.setFullYear(s.getUTCFullYear() + years);
  }
  // Get estimate of months
  months = e.getUTCMonth() - s.getUTCMonth();
  months += months < 0? 12 : 0;

  // Add difference to start, adjust if greater
  s.setUTCMonth(s.getUTCMonth() + months);
  if (s > e) {
    --months;
    s = new Date(+start);
    s.setUTCFullYear(s.getUTCFullYear() + years);
    s.setUTCMonth(s.getUTCMonth() + months);
  }

  // Get remaining time difference
  timeDiff = e - s;
  days     =  timeDiff / 8.64e7 | 0;
  hours    = (timeDiff % 8.64e7) / 3.6e6 | 0;
  minutes  = (timeDiff % 3.6e6) / 6e4 | 0;
  seconds  = ((timeDiff % 6e4) / 1e3).toFixed(3);
console.log(years, months, days, hours, minutes, seconds);  
  return [years, months, days, hours, minutes, seconds];
}

// Simple caluculation of days between two ES5 date objects
function daysDifference(start,end) {
    return ((end - start) / 8.64e7).toFixed(2);
}

// Expects input in ISO8601 format: yyyy-mm-ddThh:mm:ss.sssZ
function dateFromString(s) {
  s = s.split(/\D/);
  s[6] = s[6]? ('0.'+ s[6]) * 1000 : 0;
  return new Date(Date.UTC(s[0],--s[1],s[2],s[3],s[4],s[5],s[6]));
}

function getDateDiff(start, end, precise) {
  var d = dateDifference(dateFromString(start), dateFromString(end), precise);
  return d[0] + ' years, ' + d[1] + ' months, ' + d[2] + ' days' + 
         (precise? ', ' + d[3] + ' hours, ' + d[4] + ' minutes and ' + d[5] + ' seconds' : '') ;
}

function getDaysDiff(start, end) {
  var d = daysDifference(dateFromString(start), dateFromString(end));
  return d + ' days';
}

</script>

<!-- Some HTML to show how to use it -->
<form onsubmit="this.doCalc.onclick(); return false;">
  <label for="startDate">Start date (yyyy-mm-dd)<input name="startDate" id="startDate"
   value="2012-08-09T22:15:03.22" size="25"></label>
  <br>
  <label for="endDate">End date (yyyy-mm-dd)<input name="endDate" id="endDate"
   value="2013-08-13T12:10:03.22" size="25"></label>
  <br>
  <label for="dateDifference">Date difference: <input name="dateDifference" readonly size="100"></label>
  <br>
  <label for="daysDifference">Days difference: <input name="daysDifference" readonly size="100"></label>
  <br>
  <label for="precise"><input type="checkbox" value="precise" name="precise" id="precise">Precise?</label>
  <br>
  <input type="button" value="Calculate…" name="doCalc" onclick="
    this.form.dateDifference.value = getDateDiff(this.form.startDate.value, this.form.endDate.value, 

this.form.precise.checked);
    this.form.daysDifference.value = getDaysDiff(this.form.startDate.value, this.form.endDate.value);
  ">
  <input type="reset">
</form>
于 2013-08-19T01:29:37.110 回答