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在基于类的视图中,我可以定义 forGET或 for 的方法POST。我可以以某种方式为不同的 mime 类型的响应定义特殊方法吗?

用例是 - 即使 JS 关闭,也使 AJAX 站点可用。

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1 回答 1

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import json

from django.http import HttpResponse
from django.views.generic.edit import CreateView
from myapp.models import Author

class AjaxableResponseMixin(object):
    """
    Mixin to add AJAX support to a form.
    Must be used with an object-based FormView (e.g. CreateView)
    """
    def render_to_json_response(self, context, **response_kwargs):
        data = json.dumps(context)
        response_kwargs['content_type'] = 'application/json'
        return HttpResponse(data, **response_kwargs)

    def form_invalid(self, form):
        response = super(AjaxableResponseMixin, self).form_invalid(form)
        if self.request.is_ajax():
            return self.render_to_json_response(form.errors, status=400)
        else:
            return response

    def form_valid(self, form):
        # We make sure to call the parent's form_valid() method because
        # it might do some processing (in the case of CreateView, it will
        # call form.save() for example).
        response = super(AjaxableResponseMixin, self).form_valid(form)
        if self.request.is_ajax():
            data = {
                'pk': self.object.pk,
            }
            return self.render_to_json_response(data)
        else:
            return response

class AuthorCreate(AjaxableResponseMixin, CreateView):
    model = Author
    fields = ['name']

看看文档中的这个例子: https ://docs.djangoproject.com/en/dev/topics/class-based-views/generic-editing/#ajax-example

有两种情况:表格是否有效。从那里我们有两种情况:如果请求是基于 AJAX 的(request.is_ajax)

于 2013-08-18T19:33:00.433 回答