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我试图显示多久前上传了一个视频,我似乎无法让日期对象方法在这个脚本中工作的小时和分钟。我正在编写一个名为YouMax 2.0的脚本,我一直在编辑函数 getDateDiff,我想出了这个函数的编辑。感谢您对此的任何帮助。

function getDateDiff(timestamp) {
if (null === timestamp || timestamp === "" || timestamp === "undefined") return "?";
var splitDate = ((timestamp.toString().split('T'))[0]).split('-');
var splitTime = ((timestamp.toString().split('T'))[1]).split(':');
var d1 = new Date();
var d1Y = d1.getFullYear();
var d2Y = parseInt(splitDate[0], 10);
var d1M = d1.getMonth() + 1;
var d2M = parseInt(splitDate[1], 10);
var d1D = d1.getDate();
var d2D = parseInt(splitDate[2], 10);
var d1H = d1.getHours();
var d2H = parseInt(splitTime[0], 10);
var d1T = d1.getMinutes();
var d2T = parseInt(splitTime[1], 10);
var diffInMinutes = (d1T + 59 * d1H + 23) - (d2T + 59 * d2H + 23);
if (diffInMinutes <= 1) return "1 Minute";
else if (diffInMinutes <= 59) return diffInMinutes + " Minutes";
var diffInHours = (d1H + 23 * d1M) - (d2H + 23 * d1M);
if (diffInHours <= 1) return "1 Hour";
else if (diffInHours < 23) return diffInHours + " Hours";
var diffInDays = (d1D + 30 * d1M + 12 * d1Y) - (d2D + 30 * d2M + 12 * d2Y);
if (diffInDays < 7) return diffInDays + " days";
else if (diffInDays > 7 && diffInDays < 14) return "1 week";
else if (diffInDays >= 14 && diffInDays < 30) return Math.floor(diffInDays / 7) + " weeks";
var diffInMonths = (d1M + 12 * d1Y) - (d2M + 12 * d2Y);
if (diffInMonths <= 1) return "1 month";
else if (diffInMonths < 12) return diffInMonths + " months";
var diffInYears = Math.floor(diffInMonths / 12);
if (diffInYears <= 1) return "1 year";
else if (diffInYears < 12) return diffInYears + " years";
}

我的新功能只返回分钟和其他,不会更新到日期的变化

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2 回答 2

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I assume you are fetching the timestamp from a mysql database. This was also answered here. The top answer is in php but it is not really different from Javascript. I do suggest using php for this however.

于 2013-08-18T11:53:08.103 回答
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你可以看到你的分裂不正确......这工作正常......

var splitDate = ((timestamp.toString().split('T'))[0]).split('-');
var splitTime = ((timestamp.toString().split('T'))[1]).split(':');
var splitTime1 = ((splitTime[2].toString().split('Z'))[0]).split('.');

splitDate[0] = Year;
splitDate[1] = Month;
splitDate[2] = Day;

splitTime[0] = Hours;
splitTime[1] = Minutes;
splitTime1[0] = Seconds;
splitTime1[1] = MilliSeconds;

你现在可以执行任何你想要的..

于 2013-08-18T12:03:26.350 回答