我创建了一个点示例来演示我的问题。
会员可以奖励其他会员积分,我正在尝试构建一个查询,该查询将显示用户拥有的积分和用户给出的积分。
数据库示例
会员,
+----+----------+
| id | username |
+----+----------+
| 1 | user1 |
| 2 | user2 |
| 3 | user3 |
+----+----------+
积分,
+-------+--------+--------+
| IDFor | IDFrom | Pointz |
+-------+--------+--------+
| 1 | 2 | 5 |
| 1 | 2 | 5 |
| 3 | 1 | 2 |
+-------+--------+--------+
我正在寻找的回报是,
+-----------+--------+-------+
| username | Pointz | Given |
+-----------+--------+-------+
| user1 | 10 | 2 |
| user2 | 0 | 10 |
| user3 | 2 | 0 |
+-----------+--------+-------+
我的两个查询都返回,
+-----------+--------+-------+
| username | Pointz | Given |
+-----------+--------+-------+
| user1 | 10 | 4 |
| user2 | 0 | 10 |
| user3 | 2 | 0 |
+-----------+--------+-------+
http://sqlfiddle.com/#!2/32ae6/6
SELECT a.`username`, sum(a.`Pointz`), sum(b.`Pointz`) FROM
(SELECT * FROM `members`
LEFT JOIN `Example`.`Points` AS p ON `members`.`id` = p.`IDFor` ) AS a
LEFT JOIN
(SELECT * FROM `members`
LEFT JOIN `Example`.`Points` AS n ON `members`.`id` = n.`IDFrom` ) AS b
ON a.id = b.id
GROUP BY a.`id`
http://sqlfiddle.com/#!2/32ae6/7
SELECT `members`.`username`,sum(p.`Pointz`),sum(n.`Pointz`)
FROM `members`
LEFT JOIN `Example`.`Points` as p ON p.`IDFor` = `members`.`id`
LEFT JOIN `Example`.`Points` as n ON n.`IDFrom` = `members`.`id`
GROUP BY `members`.`id`
似乎是一个弹出但没有找到解决方案的常见问题,我所有其他类似问题的尝试都没有很好地结束,谢谢大家。