5

我需要从给定的字符串中删除多个子字符串。例子 -

String[] exclude = {"one","two","three"};
String input = "if we add one and two we get three"

我希望我的程序从输入字符串中删除所有出现的“一”或“二”或“三”并返回 -

"if we add and we get"

我如何在 Java 中做到这一点？

4

4 回答 4

5

虽然问题已经得到解答，但我对字符串替换性能很感兴趣并做了一个小测试。因此，我只是为所有对结果感兴趣的人添加了我的示例代码。我以这种方式编写了测试，您还可以添加其他替换策略来测试您自己的。

我有一个测试驱动程序（没有 JUnit 可以更轻松地复制和粘贴）

public class StringReplaceTest {

    public static void main(String[] args) {
        int iterations = 1000000;

        String[] exclude = { "one", "two", "three" };
        String input = "if we add one and two we get three";

        StringRemove replaceAll = new StringReplaceAll();
        StringRemove replace = new StringReplace();
        StringRemove stringUtilsRemove = new StringUtilsRemove();

        // check if the replacement is implemented correctly
        assertStringRemove(replaceAll);
        assertStringRemove(replace);
        assertStringRemove(stringUtilsRemove);

        profileStringRemove(replaceAll, input, exclude, iterations);
        profileStringRemove(replace, input, exclude, iterations);
        profileStringRemove(stringUtilsRemove, input, exclude, iterations);

    }

    private static void assertStringRemove(StringRemove stringRemove) {
        String[] exclude = { "one", "two", "three" };
        String input = "if we add one and two we get three";
        String replaced = stringRemove.remove(input, exclude);

        String expected = "if we add  and  we get ";
        if (!expected.equals(replaced)) {
            throw new IllegalStateException(
                    "String was not replaced correctly. Excpected <" + expected
                            + "> but was <" + replaced + ">");
        }
    }

    private static void profileStringRemove(StringRemove stringRemove,
            String input, String[] subStringsToRemove, int iterations) {
        long start = System.currentTimeMillis();
        int testCount = iterations;
        while (iterations-- > 0) {
            stringRemove.remove(input, subStringsToRemove);
        }
        long end = System.currentTimeMillis();
        printSummery(stringRemove.getClass().getSimpleName(), testCount, start,
                end);
    }

    private static void printSummery(String action, int iterations, long start,
            long end) {
        System.out.println(action + " took: " + (end - start) + " ms for "
                + iterations + " iterations");
    }

以及不同的字符串替换策略：

public interface StringRemove {

    public String remove(String input, String... subStringsToRemove);
}

public class StringReplaceAll implements StringRemove {

    public String remove(String input, String... subStringsToRemove) {
        for (int ix = 0; ix < subStringsToRemove.length; ix++) {
            input = input.replaceAll(subStringsToRemove[ix], "");
        }
        return input;
    }

}

public class StringReplace implements StringRemove {

    public String remove(String input, String... subStringsToRemove) {
        for (int ix = 0; ix < subStringsToRemove.length; ix++) {
            int replaceLength = 0;
            while (replaceLength != input.length()) {
                input = input.replace(subStringsToRemove[ix], "");
                replaceLength = input.length();
            }
        }
        return input;
    }

}

public class StringUtilsRemove implements StringRemove {

    public String remove(String input, String... subStringsToRemove) {
        for (int ix = 0; ix < subStringsToRemove.length; ix++) {
            input = StringUtils.remove(input, subStringsToRemove[ix]);
        }
        return input;
    }

}

我电脑上的结果是：

StringReplaceAll took: 3456 ms for 1000000 iterations
StringReplace took: 3162 ms for 1000000 iterations
StringUtilsRemove took: 761 ms for 1000000 iterations
于 2013-08-18T08:46:49.233 回答
3

您可以循环数组并将输入中出现的每个字符串替换为空字符串：

for(String str : exclude){
    input = input.replace(str, "");
}
于 2013-08-18T07:50:21.110 回答
3

如果没有 StringUtils，您可以像这样实现它：

String[] exclude = {"one","two","three"};
String input = "if we add one and two we get three";
for (int ix = 0; ix < exclude.length; ix++) {
    input.replaceAll(exclude[ix], "");
}
于 2013-08-18T07:53:25.797 回答
2 
for(String s:exclude){
    input=input.replace(s,"");
}
于 2013-08-18T07:49:23.933 回答