java - Hibernate 是否支持 UNION ALL？

Question

我是一名部分 UI 开发人员，现在我需要转入 Hibernate 开发。今天，当我尝试使用 UNION ALL 时，我在 HQL 中遇到了一个问题，这里是 HQL：

SELECT COUNT(DISTINCT users.userId) AS totalSize FROM (SELECT DISTINCT 
d1.sponsor.id AS userId FROM Dating d1 WHERE d1.invitee.id = ? UNION ALL 
SELECT DISTINCT d2.invitee.id AS userId FROM Dating d2 WHERE d2.sponsor.id = ?) 
AS users 

它显示如下错误：

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: ( near line 1, column 55

然后我尝试将此 HQL 转换为原始 SQL：

SELECT COUNT(DISTINCT users.userId) AS totalSize FROM (SELECT DISTINCT 
d1.sponsorId AS userId FROM mmy_dating d1 WHERE d1.inviteeId = 6 UNION 
ALL SELECT DISTINCT d2.inviteeId AS userId FROM mmy_dating d2 WHERE 
d2.sponsorId = 6) AS users;

它通常会显示正确的结果，所以我在想 Hibernate 是否不支持 UNION ALL 语法？

提前致谢。

Answer 1

此https://hibernate.atlassian.net/browse/HHH-1050仍有一个功能请求开放。还可以看看Hibernate Union 的替代品

Answer 2

想分享一下，就我而言，我发现了一种绕过这种情况的情况。这里唯一的规则是具有相同的类型，在这种情况下，对应于返回列表的 String 可以添加任意数量的表：

public List<String> findByCPForCNPJ(String query){
    TypedQuery<String> ccpf = manager.createQuery("select cpf from PessoaFisica where cpf like :pCpf", String.class);
    ccpf.setParameter("pCpf", "%" + query + "%");
    List<String> lista1 = ccpf.getResultList();

    TypedQuery<String> ccnpj = manager.createQuery("select cnpj from PessoaJuridica where cnpj like :pCnpj", String.class);
    ccnpj.setParameter("pCnpj", "%" + query + "%");

    lista1.addAll(ccnpj.getResultList());
    return lista1;
}

我希望我贡献了一点，祝大家好运......