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我正在构建一个非常简单的 cms。
其中的两个对象是文章标签 这是我目前拥有的数据库模式:

示意图 ERD

使用它,我可以按标签获取文章列表SELECT ... WHERE web_tag.Name = 'News'


问题

如何获取不包含标签的文章列表

我试着做

SELECT ... WHERE web_tag.Name != 'News'

如果文章只有一个标签,则此方法有效。如果文章明显有多个标签,它将不起作用

非常感谢!

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2 回答 2

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一种方法

SELECT a.id_article, a.name
  FROM web_article a
 WHERE NOT EXISTS
(
  SELECT *
    FROM web_tag_to_article ta JOIN web_tag t
      ON ta.id_tag = t.id_tag
   WHERE id_article = a.id_article
     AND t.name = 'News'
)

或者

SELECT id_article, name
  FROM web_article
 WHERE id_article NOT IN
(
  SELECT id_article
    FROM web_tag_to_article ta JOIN web_tag t
      ON ta.id_tag = t.id_tag
   GROUP BY id_article
  HAVING MAX(t.name = 'News') = 1
)

或者

SELECT a.id_article, a.name
  FROM web_article a LEFT JOIN web_tag_to_article ta 
    ON a.id_article = ta.id_article LEFT JOIN web_tag t
    ON ta.id_tag = t.id_tag
 GROUP BY a.id_article, a.name
HAVING MAX(COALESCE(t.name,'') = 'News') = 0

这是SQLFiddle演示

于 2013-08-17T03:34:46.450 回答
0

另一种方式

select ID_Articles, Name, Slug from web_article where ID_Article in (select ID_Articles from web_article except (select ID_Article from web_tag_to_Article where ID_Tag in (select ID_Tag from web_tag where name='news'))

于 2013-08-17T05:28:48.533 回答