php - generate unique ID for on foreach loop?

Question

Current I use toggle to show/hide details. I need to give each div a unique ID in foreach loop. I'm not sure how to make it works on an echo string. Can you help me?

<?php
$i = 0; 
    foreach ( $payment as $payment_id => $items ) {
        foreach ( $items as $item ) {
            $i++;
            $count = 0;
            // Echo, need to show unique ID in both $count, it must be the same
            echo '<p><strong><a href="#">Link</a></strong>
            <br/><a href="#" class="show_info" id="'.$count.'">Show Details</a>
            <div id="payment_info_'.$count.'" style="display:none;">';
            ++count;
        }
    }
?>

I need to make $count in 2 position on the code is same. I got error with this code.

Thank you

Updated: Actually the code is not just as I give here. I tried with your code but doesnt work.

You can view full at http://www.codesend.com/view/7d58acb2b1c51149440984ec6568183d/ (pasw:123123)

Answer 1

1. 你写++count的不是++$count
2. 看来你没有使用$i.
3. 您正在$count对每个循环进行初始化。

这应该有效：

<?php
$i = 0; /* Seems redundant */
$count = 0;
    foreach ( $payment as $payment_id => $items ) {
        foreach ( $items as $item ) {
            $i++; /* Seems redundant */
            // Echo, need to show unique ID in both $count, it must be the same
            echo '<p><strong><a href="#">Link</a></strong>
            <br/><a href="#" class="show_info" 
                    id="dtls'.$count.'">Show Details</a>
            <div id="payment_info_'.$count.'" style="display:none;">';
            ++$count;
        }
    }
?>

Answer 2

第一的：

删除它或将其放在 foreach 循环之外：

$count = 0;

第二：

不要只使用数字作为id并将其与这样的字符或单词一起使用：

id = "element'.$count.'"

第三 ：

什么是$i？

如果没用就删！

向前

更改++count为++$count

代码 ：

<?php
$i = 0; 
$count = 0;
    foreach ( $payment as $payment_id => $items ) {
        foreach ( $items as $item ) {
            $i++;
            // Echo, need to show unique ID in both $count, it must be the same
            echo '<p><strong><a href="#">Link</a></strong>
            <br/><a href="#" class="show_info" id="info_'.$count.'">Show Details</a>
            <div id="payment_info_'.$count.'" style="display:none;">';
            ++$count;
        }
    }
?>

Answer 3

++count错误，应该是 ++$count；

尝试这个

<?php
$i = 0; 
    foreach ( $payment as $payment_id => $items ) {
        foreach ( $items as $item ) {
            $i++;
            $count = 0;
            // Echo, need to show unique ID in both $count, it must be the same
            echo '<p><strong><a href="#">Link</a></strong>
            <br/><a href="#" class="show_info" id="'.$count.'">Show Details</a>
            <div id="payment_info_'.$count.'" style="display:none;">';
            ++$count;
        }
    }
?>