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出于某种原因,这适用于运行 iOS 6+ 的模拟器,但不适用于运行 iOS 5+ 的实际 iPad。当我在 iPad 上运行我的应用程序时,它给了我这个错误(和其他错误)。

Error parsing JSON: Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn’t be completed. (Cocoa error 3840.)" (Badly formed object around character 316.) UserInfo=0x650260 {NSDebugDescription=Badly formed object around character 316.}

JSON used is this (which is passed from Javascript): {"functionname":"setItem","args":{"key":"http://localhost:3000/assets/tasks/task.js","value":"function Task(){this.steps=new Array,this.completed=!1,this.loaded=!1,this.stepCount=-1,this.points=0,this.newpoints=0,this.prevpoints=0,this.circleGesture=!1,this.customGesture=!1,this.subtaskCounter=0,this.className=/"/"}(goes on for a while since it is a js script)"}}

在iOS中将json字符串转换为json的代码

if ([[urlStr lowercaseString] hasPrefix:protocolPrefix])
{
    //strip protocol from the URL. We will get input to call a native method
    urlStr = [urlStr substringFromIndex:protocolPrefix.length];

    //Decode the url string
    urlStr = [urlStr stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    NSError *jsonError;

    //parse JSON input in the URL
    NSDictionary *callInfo = [NSJSONSerialization
                              JSONObjectWithData:[urlStr dataUsingEncoding:NSUTF8StringEncoding]
                              options:0
                              error:&jsonError];

    //check if there was error in parsing JSON input
    if (jsonError != nil)
    {
        NSLog(@"Error parsing JSON: %@",[jsonError debugDescription]);
        NSLog(@"%@", urlStr);
        return NO;
    } 

    ....
}

咖啡脚本

callNativeFunction: (func, args, callback)->
  if global_phone_os == 'ios'
    url = "js2native://"
    callInfo = {}
    callInfo.functionname = func
    if args?
      callInfo.args = args
    if callback?
      cid = Math.random().toString(36).substr(2,10)
      @callback[cid] = callback
      callInfo.callback_id = cid
    url += JSON.stringify callInfo
    @openCustomURLinIFrame url

任何想法如何让它在模拟器和实际设备上工作?

更新

到目前为止,我想我已经解决了。如果我这样做了,这将被标记为答案。我必须在咖啡脚本中执行以下操作:

url += encodeURIComponent JSON.stringify callInfo

那有所作为。

谢谢。

4

2 回答 2

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在我看来,您正在尝试解析 url 字符串而不是解析 URL 内容。你确定这在模拟器中有效吗?

您的代码:

//parse JSON input in the URL
NSDictionary *callInfo = [NSJSONSerialization
                          JSONObjectWithData:[urlStr dataUsingEncoding:NSUTF8StringEncoding]
                          options:0
                          error:&jsonError];

我认为应该是:

//parse JSON input in the URL
NSDictionary *callInfo = [NSJSONSerialization
                          JSONObjectWithData:[NSData dataWithContentsOfURL:
                urlStr],
                          options:0
                          error:&jsonError];
于 2013-08-16T23:49:41.900 回答
0

这确实解决了这个问题。

url += encodeURIComponent JSON.stringify callInfo
于 2013-08-27T23:10:01.560 回答