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为什么 ShowDialog() 显示旧消息?

我为 ShowDialog 输入了“测试消息”,然后将其更改为新消息。但它仍然显示“测试消息”

新代码

private void addButton_Click(object sender, EventArgs e)
    {
        //MessageBox.Show("Debugging Add Test Button", "My Test Application",
        //MessageBoxButtons.OKCancel, MessageBoxIcon.Asterisk);

        //Display Add Alarm form
        AlarmForm alarmForm = new AlarmForm();

        //Display alarmForm instance, assgn the results to a Dialog result
        DialogResult dialogResult = alarmForm.ShowDialog();

        //Check return value, and extract data
        if (dialogResult == DialogResult.OK)  // Add Alarm 
        {

            //Extract Alarm information from the Form using the accessor
            Alarm alarm = alarmForm.Alarm;
            //Add the alarm object to our list
            _alarms.Add(alarm);

            //Update the Listbox
            refreshAlarmList();
        }
    }

旧代码

private void addButton_Click(object sender, EventArgs e)
     {
        MessageBox.Show("Debugging Add Button", "My Application",
        MessageBoxButtons.OKCancel, MessageBoxIcon.Asterisk);
    }

关于造成这种情况的任何想法?我已尝试删除代码,添加新消息并将其注释掉。

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1 回答 1

-1

听起来像一个缓存问题。我会尝试清除您的浏览器缓存并重试。

于 2013-08-16T22:26:58.123 回答