sql - 如果 1 个字段不同，如何将多个值插入行

Question

对，我有以下数据需要插入到名为 locals 的表中，但我只想在 locals 表中不存在街道字段时插入它。数据和字段如下：

Street    PC       Locality
------------------------------
Street1   ABC xyz  A
Street2   DEF xyz  B

依此类推，但如果 Street 字段尚未出现在 locals 表中，我想插入到 Locals 表中。

我正在考虑使用以下内容：

INSERT
  INTO Locals (Street,PC,Locality) 
       (
            SELECT DISTINCT s.Street
              FROM Locals_bk s
             WHERE NOT EXISTS (
                      SELECT 1
                        FROM Locals l
                       WHERE s.Street = l.Street
                   )
       )
     ;

但我意识到这只会插入街道字段而不是同一行的其余数据。

Answer 1

insert into Locals (Street, PC, Locality) 
select b.Street, b.PC, b.Locality
from Locals_bk as b
where not exists (select * from Locals as t where t.street = b.street)

或者

insert into Locals (Street, PC, Locality) 
select b.Street, b.PC, b.Locality
from Locals_bk as b
where b.street not in (select t.street from Locals as t)

Answer 2

怎么样

INSERT [Locals]
SELECT
            [Street],
            [PC],
            [Locality]
    FROM
            [Locals_bk] bk
    WHERE
         NOT EXIST (
             SELECT * FROM [Locals] l WHERE l.[Street] = bk.[Street]
         );

Answer 3

您可以使用 NOT IN ：

    INSERT into Locals (Street,PC,Locality) 
    SELECT s.Street, s.PC, s.Locality
    FROM Locals_bk as s
    WHERE NOT IN (SELECT * FROM Locals as t WHERE t.street = s.street)

Answer 4

以下从与街道匹配的任意行中获取所需的字段：

insert into Locals (Street, PC, Locality) 
select s.Street, s.PC, s.Locality
from (select s.*, row_number() over (partition by s.Street order by (select NULL)) as seqnum
      from Locals_bk s
     ) s
where seqnum = 1 and
     NOT EXISTS (SELECT 1
                  FROM Locals l
                  WHERE s.Street = l.Street);

如果您知道这些值始终相同，则可以这样做：

insert into Locals (Street, PC, Locality) 
select distinct s.Street, s.PC, s.Locality
from Locals_bk s
where NOT EXISTS (SELECT 1
                  FROM Locals l
                  WHERE s.Street = l.Street);