3

我有一个看起来像这样的表：

r01 r02 r03 r04
1   2   X   X
1   2   X   1
X   1   2   1
X   2   2   2
1   2   1   X
1   1   1   2
1   X   1   1
1   2   X   1
2   2   X   2

我想为每一列（不是行）获取一个频率数组列表，类似于array_count_values(). 喜欢

r01: 1 => 6, X => 2, 2 => 1
r02: 1 => 2, X => 1, 2 => 6
r03: 1 => 3, X => 4, 2 => 2
r04: 1 => 4, X => 2, 2 => 3

是否有可能解决一个或几个 mysql 问题？我还没有想出和主意。我唯一的解决方案是将所有数据获取到 PHP，然后有一个数据数组，并为每一行的相应计数器添加一个。

我可以有 100->20000 行。所以我想要一个 mysql 解决方案，它可以比 PHP 解决方案更好地扩展。

- 编辑

我正在显示一个简化的表格结构，但我认为我需要显示完整的表格。

CREATE TABLE IF NOT EXISTS `tips_rows` (
  `row_id` int(11) NOT NULL,
  `r01` enum('1','X','2') NOT NULL,
  `r02` enum('1','X','2') NOT NULL,
  `r03` enum('1','X','2') NOT NULL,
  `r04` enum('1','X','2') NOT NULL,
  `r05` enum('1','X','2') NOT NULL,
  `r06` enum('1','X','2') NOT NULL,
  `r07` enum('1','X','2') NOT NULL,
  `r08` enum('1','X','2') NOT NULL,
  `r09` enum('1','X','2') NOT NULL,
  `r10` enum('1','X','2') NOT NULL,
  `r11` enum('1','X','2') NOT NULL,
  `r12` enum('1','X','2') NOT NULL,
  `r13` enum('1','X','2') NOT NULL,
  PRIMARY KEY (`row_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

并且tips_rows 包含值的所有组合。（1,600,000 行）我有一个链接表连接用户到tips_rows，'tips_rows_users'

因此，此链接表将为多个用户保存每个用户 100-10000 row_id 的数据集。

我找到了一个基于其他 stackoverflow 谷歌搜索的解决方案。也许不是最纯粹的查询，但它可以工作并且速度很快。

 SELECT
    SUM(CASE WHEN r01 = '1' THEN 1 ELSE 0 END) AS r11,
    SUM(CASE WHEN r01 = 'X' THEN 1 ELSE 0 END) AS r1X,
    SUM(CASE WHEN r01 = '2' THEN 1 ELSE 0 END) AS r12,
    SUM(CASE WHEN r02 = '1' THEN 1 ELSE 0 END) AS r21,
    SUM(CASE WHEN r02 = 'X' THEN 1 ELSE 0 END) AS r2X,
    SUM(CASE WHEN r02 = '2' THEN 1 ELSE 0 END) AS r22,
    SUM(CASE WHEN r03 = '1' THEN 1 ELSE 0 END) AS r31,
    SUM(CASE WHEN r03 = 'X' THEN 1 ELSE 0 END) AS r3X,
    SUM(CASE WHEN r03 = '2' THEN 1 ELSE 0 END) AS r32,
    SUM(CASE WHEN r04 = '1' THEN 1 ELSE 0 END) AS r41,
    SUM(CASE WHEN r04 = 'X' THEN 1 ELSE 0 END) AS r4X,
    SUM(CASE WHEN r04 = '2' THEN 1 ELSE 0 END) AS r42,
    SUM(CASE WHEN r05 = '1' THEN 1 ELSE 0 END) AS r51,
    SUM(CASE WHEN r05 = 'X' THEN 1 ELSE 0 END) AS r5X,
    SUM(CASE WHEN r05 = '2' THEN 1 ELSE 0 END) AS r52,
    SUM(CASE WHEN r06 = '1' THEN 1 ELSE 0 END) AS r61,
    SUM(CASE WHEN r06 = 'X' THEN 1 ELSE 0 END) AS r6X,
    SUM(CASE WHEN r06 = '2' THEN 1 ELSE 0 END) AS r62,
    SUM(CASE WHEN r07 = '1' THEN 1 ELSE 0 END) AS r71,
    SUM(CASE WHEN r07 = 'X' THEN 1 ELSE 0 END) AS r7X,
    SUM(CASE WHEN r07 = '2' THEN 1 ELSE 0 END) AS r72,
    SUM(CASE WHEN r08 = '1' THEN 1 ELSE 0 END) AS r81,
    SUM(CASE WHEN r08 = 'X' THEN 1 ELSE 0 END) AS r8X,
    SUM(CASE WHEN r08 = '2' THEN 1 ELSE 0 END) AS r82,
    SUM(CASE WHEN r09 = '1' THEN 1 ELSE 0 END) AS r91,
    SUM(CASE WHEN r09 = 'X' THEN 1 ELSE 0 END) AS r9X,
    SUM(CASE WHEN r09 = '2' THEN 1 ELSE 0 END) AS r92,
    SUM(CASE WHEN r10 = '1' THEN 1 ELSE 0 END) AS r101,
    SUM(CASE WHEN r10 = 'X' THEN 1 ELSE 0 END) AS r10X,
    SUM(CASE WHEN r10 = '2' THEN 1 ELSE 0 END) AS r102,
    SUM(CASE WHEN r11 = '1' THEN 1 ELSE 0 END) AS r111,
    SUM(CASE WHEN r11 = 'X' THEN 1 ELSE 0 END) AS r11X,
    SUM(CASE WHEN r11 = '2' THEN 1 ELSE 0 END) AS r112,
    SUM(CASE WHEN r12 = '1' THEN 1 ELSE 0 END) AS r121,
    SUM(CASE WHEN r12 = 'X' THEN 1 ELSE 0 END) AS r12X,
    SUM(CASE WHEN r12 = '2' THEN 1 ELSE 0 END) AS r122,
    SUM(CASE WHEN r13 = '1' THEN 1 ELSE 0 END) AS r131,
    SUM(CASE WHEN r13 = 'X' THEN 1 ELSE 0 END) AS r13X,
    SUM(CASE WHEN r13 = '2' THEN 1 ELSE 0 END) AS r132
    FROM `tips_rows` AS r
    INNER JOIN tips_rows_users USING (row_id)
    WHERE user__id='{userid}'

这会给我一个结果行

r11 r1X r12 r21 r2X r22 r31 r3X r32 r41 r4X r42 r51 r5X r52 r61 r6X r62 r71 r7X r72 r81 r8X r82 r91 r9X r92 r101 r10X r102 r111 r11X r112 r121 r12X r122 r131 r13X r132
40  34  26  48  30  22  69  14  17  70  16  14  15  17  68  28  31  41  80  20  0   49  29  22  38  30  32  69   16   15   29   28   43   19   31   50   13   25   62

我可以在我的 php-template 文件中使用它。

4

3 回答 3

1

尝试这个：：

Select 'R01', r01, count(1) from myTable group by r01
UNION 
Select 'R02', r02, count(1) from myTable group by r02 
UNION
Select 'R03', r03, count(1) from myTable group by r03 
UNION
Select 'R04', r04, count(1) from myTable group by r04
于 2013-08-16T09:15:39.890 回答
0

假设每列只有 4 列和 3 个可能的值，并且如果您真的希望您的结果显示为“每个值一列”：

SELECT 'R01' AS 'Row', SUM(IF(r01 = 1, 1, 0)) as '1',
                       SUM(IF(r01 = 2, 1, 0)) as '2',
                       SUM(IF(r01 = 'X', 1, 0)) as 'X'
       FROM myTable
UNION  SELECT 'R02', SUM(IF(r02 = 1, 1, 0)) as '1',
                       SUM(IF(r02 = 2, 1, 0)) as '2',
                       SUM(IF(r02 = 'X', 1, 0)) as 'X'
       FROM myTable
UNION  SELECT 'R03', SUM(IF(r03 = 1, 1, 0)) as '1',
                       SUM(IF(r03 = 2, 1, 0)) as '2',
                       SUM(IF(r03 = 'X', 1, 0)) as 'X'
       FROM myTable

UNION  SELECT 'R04', SUM(IF(r04 = 1, 1, 0)) as '1',
                       SUM(IF(r04 = 2, 1, 0)) as '2',
                       SUM(IF(r04 = 'X', 1, 0)) as 'X'
       FROM myTable

生产：

+------+----+----+---+
| ROW  | 1  | 2  | X |
+------+----+----+---+
| R01  | 6  | 1  | 2 |
| R02  | 2  | 6  | 1 |
| R03  | 3  | 2  | 4 |
| R04  | 4  | 3  | 2 |
+------+----+----+---+

见http://sqlfiddle.com/#!2/c6376/2

如果可以接受旋转结果表，则以下查询将执行得更好：

SELECT n,
       SUM(IF(r01 = n, 1, 0)) AS 'r01',
       SUM(IF(r02 = n, 1, 0)) AS 'r02',
       SUM(IF(r03 = n, 1, 0)) AS 'r03',
       SUM(IF(r04 = n, 1, 0)) AS 'r04'
FROM mytable JOIN (SELECT '1' AS n UNION SELECT '2' UNION SELECT 'X') S
GROUP BY n;

导致：

+----+------+------+------+-----+
|    | R01  | R02  | R03  | R04 |
+----+------+------+------+-----+
| 1  |   6  |   2  |   3  |   4 |
| 2  |   1  |   6  |   2  |   3 |
| X  |   2  |   1  |   4  |   2 |
+----+------+------+------+-----+
于 2013-08-16T09:37:19.767 回答
0

感谢所有不同的解决方案。我现在已经对我的数据进行了一些测试。我已经查询了 10000 行。这是我的发现。

解决方案1：

Select 'R01', r01, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r01
UNION 
Select 'R02', r02, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r02 
UNION
Select 'R03', r03, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r03 
UNION
Select 'R04', r04, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r04 
UNION
Select 'R05', r05, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r05 
UNION
Select 'R06', r06, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r06 
UNION
Select 'R07', r07, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r07 
UNION
Select 'R08', r08, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r08 
UNION
Select 'R09', r09, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r09 
UNION
Select 'R10', r10, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r10 
UNION
Select 'R11', r11, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r11 
UNION
Select 'R12', r12, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r12 
UNION
Select 'R13', r13, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r13

每次查询大约需要 0.1365 秒

解决方案2：

SELECT n,
       SUM(IF(r01 = n, 1, 0)) AS 'r01',
       SUM(IF(r02 = n, 1, 0)) AS 'r02',
       SUM(IF(r03 = n, 1, 0)) AS 'r03',
       SUM(IF(r04 = n, 1, 0)) AS 'r04',
       SUM(IF(r05 = n, 1, 0)) AS 'r05',
       SUM(IF(r06 = n, 1, 0)) AS 'r06',
       SUM(IF(r07 = n, 1, 0)) AS 'r07',
       SUM(IF(r08 = n, 1, 0)) AS 'r08',
       SUM(IF(r09 = n, 1, 0)) AS 'r09',
       SUM(IF(r10 = n, 1, 0)) AS 'r10',
       SUM(IF(r11 = n, 1, 0)) AS 'r11',
       SUM(IF(r12 = n, 1, 0)) AS 'r12',
       SUM(IF(r13 = n, 1, 0)) AS 'r13'       
FROM `tips_rows` AS r
INNER JOIN tips_rows_users USING (row_id)
JOIN (SELECT '1' AS n UNION SELECT '2' UNION SELECT 'X') S
WHERE user_id='27'
GROUP BY n;

第一次查询大约需要 0.0997 秒。可以缓存在 mysql 查询缓存中，所以第二次需要 ~0.0002s

解决方案3：

SELECT
    SUM(CASE WHEN r01 = '1' THEN 1 ELSE 0 END) AS r11,
    SUM(CASE WHEN r01 = 'X' THEN 1 ELSE 0 END) AS r1X,
    SUM(CASE WHEN r01 = '2' THEN 1 ELSE 0 END) AS r12,
    SUM(CASE WHEN r02 = '1' THEN 1 ELSE 0 END) AS r21,
    SUM(CASE WHEN r02 = 'X' THEN 1 ELSE 0 END) AS r2X,
    SUM(CASE WHEN r02 = '2' THEN 1 ELSE 0 END) AS r22,
    SUM(CASE WHEN r03 = '1' THEN 1 ELSE 0 END) AS r31,
    SUM(CASE WHEN r03 = 'X' THEN 1 ELSE 0 END) AS r3X,
    SUM(CASE WHEN r03 = '2' THEN 1 ELSE 0 END) AS r32,
    SUM(CASE WHEN r04 = '1' THEN 1 ELSE 0 END) AS r41,
    SUM(CASE WHEN r04 = 'X' THEN 1 ELSE 0 END) AS r4X,
    SUM(CASE WHEN r04 = '2' THEN 1 ELSE 0 END) AS r42,
    SUM(CASE WHEN r05 = '1' THEN 1 ELSE 0 END) AS r51,
    SUM(CASE WHEN r05 = 'X' THEN 1 ELSE 0 END) AS r5X,
    SUM(CASE WHEN r05 = '2' THEN 1 ELSE 0 END) AS r52,
    SUM(CASE WHEN r06 = '1' THEN 1 ELSE 0 END) AS r61,
    SUM(CASE WHEN r06 = 'X' THEN 1 ELSE 0 END) AS r6X,
    SUM(CASE WHEN r06 = '2' THEN 1 ELSE 0 END) AS r62,
    SUM(CASE WHEN r07 = '1' THEN 1 ELSE 0 END) AS r71,
    SUM(CASE WHEN r07 = 'X' THEN 1 ELSE 0 END) AS r7X,
    SUM(CASE WHEN r07 = '2' THEN 1 ELSE 0 END) AS r72,
    SUM(CASE WHEN r08 = '1' THEN 1 ELSE 0 END) AS r81,
    SUM(CASE WHEN r08 = 'X' THEN 1 ELSE 0 END) AS r8X,
    SUM(CASE WHEN r08 = '2' THEN 1 ELSE 0 END) AS r82,
    SUM(CASE WHEN r09 = '1' THEN 1 ELSE 0 END) AS r91,
    SUM(CASE WHEN r09 = 'X' THEN 1 ELSE 0 END) AS r9X,
    SUM(CASE WHEN r09 = '2' THEN 1 ELSE 0 END) AS r92,
    SUM(CASE WHEN r10 = '1' THEN 1 ELSE 0 END) AS r101,
    SUM(CASE WHEN r10 = 'X' THEN 1 ELSE 0 END) AS r10X,
    SUM(CASE WHEN r10 = '2' THEN 1 ELSE 0 END) AS r102,
    SUM(CASE WHEN r11 = '1' THEN 1 ELSE 0 END) AS r111,
    SUM(CASE WHEN r11 = 'X' THEN 1 ELSE 0 END) AS r11X,
    SUM(CASE WHEN r11 = '2' THEN 1 ELSE 0 END) AS r112,
    SUM(CASE WHEN r12 = '1' THEN 1 ELSE 0 END) AS r121,
    SUM(CASE WHEN r12 = 'X' THEN 1 ELSE 0 END) AS r12X,
    SUM(CASE WHEN r12 = '2' THEN 1 ELSE 0 END) AS r122,
    SUM(CASE WHEN r13 = '1' THEN 1 ELSE 0 END) AS r131,
    SUM(CASE WHEN r13 = 'X' THEN 1 ELSE 0 END) AS r13X,
    SUM(CASE WHEN r13 = '2' THEN 1 ELSE 0 END) AS r132
    FROM `tips_rows` AS r
    INNER JOIN tips_rows_users USING (row_id)
    WHERE user_id='27'

第一次和第二次大约需要 0.0587 秒。在那之后的0.0002s之后的问题。

我会选择解决方案 3。因为它有最好的最坏情况时间。但奇怪的是在缓存之前需要两次查询。

于 2013-08-17T07:52:11.310 回答