我有一个 python 脚本 parse.py，它在脚本中打开一个文件，比如 file1，然后做一些事情可能会打印出字符总数。
filename = 'file1'
f = open(filename, 'r')
content = f.read()
print filename, len(content)
现在，我正在使用 stdout 将结果定向到我的输出文件 - 输出
python parse.py >> output
但是，我不想手动逐个文件执行此文件，有没有办法自动处理每个文件？喜欢
ls | awk '{print}' | python parse.py >> output
那么问题是如何从标准中读取文件名？或者已经有一些内置函数可以轻松完成 ls 和那些工作？
谢谢！
操作系统
您可以使用以下命令列出当前目录中的所有文件os.listdir：
import os
for filename in os.listdir(os.getcwd()):
with open(os.path.join(os.getcwd(), filename), 'r') as f: # open in readonly mode
# do your stuff
全球
或者您可以仅列出一些文件，具体取决于使用glob模块的文件模式：
import glob
for filename in glob.glob('*.txt'):
with open(os.path.join(os.getcwd(), filename), 'r') as f: # open in readonly mode
# do your stuff
它不必是当前目录，您可以在任何您想要的路径中列出它们：
path = '/some/path/to/file'
for filename in glob.glob(os.path.join(path, '*.txt')):
with open(os.path.join(os.getcwd(), filename), 'r') as f: # open in readonly mode
# do your stuff
管道
或者你甚至可以使用你指定的管道fileinput
import fileinput
for line in fileinput.input():
# do your stuff
然后您可以将它与管道一起使用：
ls -1 | python parse.py
您应该尝试使用os.walk.
import os
yourpath = 'path'
for root, dirs, files in os.walk(yourpath, topdown=False):
for name in files:
print(os.path.join(root, name))
stuff
for name in dirs:
print(os.path.join(root, name))
stuff
我一直在寻找这个答案：
import os,glob
folder_path = '/some/path/to/file'
for filename in glob.glob(os.path.join(folder_path, '*.htm')):
with open(filename, 'r') as f:
text = f.read()
print (filename)
print (len(text))
您也可以选择 '*.txt' 或文件名的其他结尾
您实际上可以只使用os 模块来做这两个：
import os #os module imported here
location = os.getcwd() # get present working directory location here
counter = 0 #keep a count of all files found
csvfiles = [] #list to store all csv files found at location
filebeginwithhello = [] # list to keep all files that begin with 'hello'
otherfiles = [] #list to keep any other file that do not match the criteria
for file in os.listdir(location):
try:
if file.endswith(".csv"):
print "csv file found:\t", file
csvfiles.append(str(file))
counter = counter+1
elif file.startswith("hello") and file.endswith(".csv"): #because some files may start with hello and also be a csv file
print "csv file found:\t", file
csvfiles.append(str(file))
counter = counter+1
elif file.startswith("hello"):
print "hello files found: \t", file
filebeginwithhello.append(file)
counter = counter+1
else:
otherfiles.append(file)
counter = counter+1
except Exception as e:
raise e
print "No files found here!"
print "Total files found:\t", counter
现在，您不仅列出了文件夹中的所有文件，而且还（可选）按起始名称、文件类型等对它们进行了排序。现在遍历每个列表并做你的事情。
import pyautogui
import keyboard
import time
import os
import pyperclip
os.chdir("target directory")
# get the current directory
cwd=os.getcwd()
files=[]
for i in os.walk(cwd):
for j in i[2]:
files.append(os.path.abspath(j))
os.startfile("C:\Program Files (x86)\Adobe\Acrobat 11.0\Acrobat\Acrobat.exe")
time.sleep(1)
for i in files:
print(i)
pyperclip.copy(i)
keyboard.press('ctrl')
keyboard.press_and_release('o')
keyboard.release('ctrl')
time.sleep(1)
keyboard.press('ctrl')
keyboard.press_and_release('v')
keyboard.release('ctrl')
time.sleep(1)
keyboard.press_and_release('enter')
keyboard.press('ctrl')
keyboard.press_and_release('p')
keyboard.release('ctrl')
keyboard.press_and_release('enter')
time.sleep(3)
keyboard.press('ctrl')
keyboard.press_and_release('w')
keyboard.release('ctrl')
pyperclip.copy('')
下面的代码读取包含我们正在运行的脚本的目录中可用的任何文本文件。然后它打开每个文本文件并将文本行的单词存储到一个列表中。存储单词后，我们逐行打印每个单词
import os, fnmatch
listOfFiles = os.listdir('.')
pattern = "*.txt"
store = []
for entry in listOfFiles:
if fnmatch.fnmatch(entry, pattern):
_fileName = open(entry,"r")
if _fileName.mode == "r":
content = _fileName.read()
contentList = content.split(" ")
for i in contentList:
if i != '\n' and i != "\r\n":
store.append(i)
for i in store:
print(i)