c# - C# 控制台应用程序根据文件名将文件移动到特定目录

Question

样本文件名：S012311d130614t095121.14194092001

左边的第九个字符是日期（130614）然后我想根据日期将此文件存储在以下目录中：

1306/         (year-month)
  130614/     (year-month-day)
    S012311d130614t095121.14194092001

Answer 1

如果我理解正确：

string input = Path.GetFileName(originalFile);
     //"S012311d130614t095121.14194092001";

string yearMonthDay = input.Substring(8, 6);

string yearMonth = yearMonthDay.Substring(0, 4);
Console.WriteLine(yearMonth);

string folder = Path.Combine(Path.Combine(rootFolder, yearMonth), yearMonthDay);
Directory.CreateDirectory(folder);

// Write to folder
File.Copy(originalFile, Path.Combine(folder, input);

这将保证在rootFolderwith下存在一个文件夹1306\130614，并为您提供创建文件夹的文件夹名称。

Answer 2

DateTime首先，从文件名中获取值的扩展方法：

public static class FileInfoHelpers
{
    private static Regex rxIso8601DateTimeValue = new Regex( @"\d{6,6}[Tt]\d{6,6}(\.\d+)$");
    private static readonly string[] formats = new string[]{
                                                    @"yyMMdd\tHHmmss.fffffff" ,
                                                    @"yyMMdd\THHmmss.fffffff" ,
                                                    } ;
    public static DateTime? TimestampFromName( this FileInfo fi )
    {
        DateTime? value = null ;
        Match m = rxIso8601DateTimeValue.Match( fi.Name ) ;
        if ( m.Success )
        {
            DateTime dt ;
            bool success = DateTime.TryParseExact( m.Value , formats , CultureInfo.InvariantCulture , DateTimeStyles.None , out dt  ) ;
            value = success ? dt : (DateTime?)null ;
        }
        return value ;
    }
}

那么你只需要这样的东西：

// establish the source and target directories
// ensuring that they both exist
DirectoryInfo source = Directory.CreateDirectory( @"C:\some\directory\with\files\to\move" ) ;
DirectoryInfo target = Directory.CreateDirectory( @"C:\repository" ) ;

// save the current working directory
string prevCwd = Environment.CurrentDirectory ;

try
{

  // make the destination root the current working directory
  Environment.CurrentDirectory = target.FullName ;

  // enumerate over the files in the source directory
  foreach ( FileInfo fi in source.EnumerateFiles() )
  {
    // parse a datetime out of the file name
    DateTime? timestamp = fi.TimestampFromName() ;

    // if we didn't find a valid datetime value in the file name, skip this file
    if ( !timestamp.HasValue ) continue ;

    // construct the relative path of the archive subdirectory        
    // and ensure that it exists
    string relativeSubdir = timestamp.Value.ToString("yyMM\\yyMMdd") ;
    DirectoryInfo subdir = target.CreateSubdirectory( relativeSubdir ) ;

    // build a relative path to the file's desired location
    // and move it there.
    string destination = Path.Combine( relativePath , fi.Name ) ;
    fi.MoveTo( destination ) ;

  }

}
finally
{
  // restore the original CWD
  Environment.CurrentDirectory = prevCwd ;
}

简单的！

Answer 3

您可以使用以下代码获取目录中的所有文件（文件名）：

string[] filePaths = Directory.GetFiles(@"Directory");

然后使用 for-each 获取每个字符串一个该字符串数组并检查每个字符串的第九个字符（我不会为此发布代码，对你来说有点工作）

使用以下代码复制您的文件：

System.IO.File.Copy(originFile, destFile, true);

结合所有这些以实现您的目标。