plot - 在 gnuplot 的一行上绘制许多文件顺序

Question

我必须绘制 10 个具有相同图例的文件，但我还需要在文件中排序数字，因为当我在 gnuplot 上写一行时，它会显示一些不好的图像。有些数字必须在其他数字之前才能在我的图表上显示一条连续线。看着红线可以明白我的意思。有没有办法做到这一点？

plot '<paste ../00/Statistic100.txt ../01/Statistic100.txt ../02/Statistic100.txt ../03/Statistic100.txt ../04/Statistic100.txt ../05/Statistic100.txt ../06/Statistic100.txt ../07/Statistic100.txt ../08/Statistic100.txt ../09/Statistic100.txt' with linespoint ls 1 title 'Reputation until 100%'

提前致谢！费利佩

Answer 1

Use smooth unique after the plot command.

From the gnuplot documentation:

The unique option makes the data monotonic in x; points with the same x-value are replaced by a single point having the average y-value. The resulting points are then connected by straight line segments.

Example

Without ordering

plot "-" with lines
 0   3
 2   4
-2   2
-5  -1
 1   5
 5   6
-1  -3
 4   0
-3  -3
 3  -4
-4   1
e

Result:

With ordering

plot "-" smooth unique with lines
 0   3
 2   4
-2   2
-5  -1
 1   5
 5   6
-1  -3
 4   0
-3  -3
 3  -4
-4   1
e

Result: