2

我有一个程序要求输入一个数字（int x）。然后，用户应该在控制台输入 x 个数字。控制台应该将所有数字加在一起并写出所有输入数字的结果。所以我这样做了：

Console.WriteLine("Enter an number: ");
int x = int.Parse(Console.ReadLine());

for (int i = 0; i < x; i++ )
{
    Console.WriteLine("Ange tal {0}: ",i );
    double numbers= double.Parse(Console.ReadLine());
}

Console.WriteLine("Sum of the entered numbers are: {0} ",x);
Console.ReadLine();

但结果只给了我最后输入的数字。我究竟做错了什么？

4

7 回答 7

3

您需要创建一个变量来存储数字的总和 ( sum)。然后，在您阅读下一个数字后，您应该将其添加到您的总和中。

Console.WriteLine("Enter a number: ");
int x = int.Parse(Console.ReadLine());
double sum = 0;
for (int i = 0; i < x; i++ )
{
   Console.WriteLine("Ange tal {0}: ", i);
   double number = double.Parse(Console.ReadLine());
   sum += number;
}

Console.WriteLine("Sum of the entered numbers is: {0}", sum);
Console.ReadLine();
于 2013-08-15T12:57:14.457 回答
1 
    Console.Write("Enter N number: ");
    double numberN = double.Parse(Console.ReadLine());
    double sum = 0;

    for (double i = 0; i < numberN; i++)
    {

        Console.Write("Enter number: ");
        double number = double.Parse(Console.ReadLine());
        sum += number;

    }

    Console.WriteLine("The sum is: {0}", sum);
于 2015-09-30T18:35:18.820 回答
0

这里有代码，Write格式WriteLine正确。

Console.Write("Enter an number: ");
int x = int.Parse(Console.ReadLine());

double sum = 0;

for (int i = 0; i < x; i++)
{
    Console.Write("Ange tal {0}: ", i);
    double number = double.Parse(Console.ReadLine());
    sum = sum + number;
}

Console.WriteLine("Sum of the entered numbers are: {0:R} ", sum);
Console.Write("Press a key to exit");
Console.ReadKey();

但现在我们想更进一步：尝试插入：

2
0.1
0.2

（或者0,1，0,2如果您,用作小数点分隔符）

我一直认为OMG小马！！！（Aka Humanity：Epic Fail）是最好的读物……

于 2013-08-15T13:05:04.540 回答
0

你可以这样做

Console.WriteLine("Enter an number: ");
int x = int.Parse(Console.ReadLine());
List<double> allNumbers = new List<double>();
for (int i = 0; i < x; i++ )
{
      Console.WriteLine("Ange tal {0}: ",i );
      double temp;
      if(double.TryParse(Console.ReadLine(), out temp))
         allNumbers.Add(temp);
      else
          Console.WriteLine("Enter a valid number");  
}

Console.WriteLine("Sum of the entered numbers are: {0} ",allNumbers.Sum());
Console.ReadLine();
于 2013-08-15T12:58:40.043 回答
0

这样将显示输入数字的总和

Console.WriteLine("Enter an number: ");
        int x = int.Parse(Console.ReadLine());
        double sum = 0
        for (int i = 0; i < x; i++ )
        {
            Console.WriteLine("Ange tal {0}: ",i );
            sum = sum + double.Parse(Console.ReadLine());

        }

        Console.WriteLine("Sum of the entered numbers are: {0} ",sum);
        Console.ReadLine();
于 2013-08-15T12:57:29.190 回答
0

您实际上从未在代码中进行任何求和。

double sum = 0;
for (int i = 0; i < x; i++ )
{
    Console.WriteLine("Ange tal {0}: ",i );
    double numbers= double.Parse(Console.ReadLine());
    sum += numbers;
}

    Console.WriteLine("Sum of the entered numbers are: {0} ",sum);
于 2013-08-15T12:58:32.060 回答
0 
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace add

{
    class Program
    {
        static void Main(string[] args)
        {
            int a,b,c;
            Console.WriteLine("Enter the first number");
            a = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Enter second number");
            b = Convert.ToInt32(Console.ReadLine());
            c = a + b;
            Console.WriteLine("The addition of two number is {0}", c);
            Console.ReadLine();
        }
    }
}
于 2014-07-02T15:50:18.263 回答