33 
@Path("file.upload")
public class UploadFileService {
@POST
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
        @FormDataParam("file") InputStream uploadedInputStream,
        @FormDataParam("file") FormDataContentDisposition fileDetail) {

    System.out.println("-----------------UploadFileService------------------1.");
    // Should we use a disk or DB? Decided to use DISK
    // Path should be read from properties-files
    String uploadedFileLocation = "//uploaded/" + fileDetail.getFileName();

    // save it
    writeToFile(uploadedInputStream, uploadedFileLocation);

    String output = "File uploaded to : " + uploadedFileLocation;
    // All went OK
    return Response.status(200).entity(output).build();

}

 WARNING: No injection source found for a parameter of type public javax.ws.rs.core.Response com.insame.service.UploadFileService.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition) at index 0.

SEVERE:   WebModule[/insame]StandardWrapper.Throwable
org.glassfish.jersey.server.model.ModelValidationException: Validation of the application resource model has failed during application initialization.
[[FATAL] No injection source found for a parameter of type public javax.ws.rs.core.Response com.insame.service.UploadFileService.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition) at index 0.; source='ResourceMethod{httpMethod=POST, consumedTypes=[multipart/form-data], producedTypes=[], suspended=false, suspendTimeout=0, suspendTimeoutUnit=MILLISECONDS, invocable=Invocable{handler=MethodHandler{handlerClass=class com.insame.service.UploadFileService, handlerConstructors=[org.glassfish.jersey.server.model.HandlerConstructor@47bee27a]}, handlingMethod=public javax.ws.rs.core.Response com.insame.service.UploadFileService.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition), parameters=[Parameter [type=class java.io.InputStream, source=file, defaultValue=null], Parameter [type=class com.sun.jersey.core.header.FormDataContentDisposition, source=file, defaultValue=null]], responseType=class javax.ws.rs.core.Response}, nameBindings=[]}']
    at org.glassfish.jersey.server.ApplicationHandler.initialize(ApplicationHandler.java:410)
    at org.glassfish.jersey.server.ApplicationHandler.access$500(ApplicationHandler.java:157)
    at org.glassfish.jersey.server.ApplicationHandler$3.run(ApplicationHandler.java:280)
    at org.glassfish.jersey.internal.Errors$2.call(Errors.java:289)
    at org.glassfish.jersey.internal.Errors$2.call(Errors.java:286)
    at org.glassfish.jersey.internal.Errors.process(Errors.java:315)
    at org.glassfish.jersey.internal.Errors.process(Errors.java:297)
    at org.glassfish.jersey.internal.Errors.processWithException(Errors.java:286)
    at org.glassfish.jersey.server.ApplicationHandler.<init>(ApplicationHandler.java:277)
    at org.glassfish.jersey.servlet.WebComponent.<init>(WebComponent.java:262)
    at org.glassfish.jersey.servlet.ServletContainer.init(ServletContainer.java:167)

我在下面实现了这样的测试服务UploadFileService：

@GET
@Path("count")
@Produces("text/plain")
public String countREST() {
    return "1 one 1";
}

我得到了这个异常记录：

FINE:   [Web-Security] hasResource perm: ("javax.security.jacc.WebResourcePermission" 

"/webresources/file.upload/count" "GET")
SEVERE:   WebModule[/insame]StandardWrapper.Throwable
java.lang.IllegalStateException: The resource configuration is not modifiable in this context.
    at org.glassfish.jersey.server.ResourceConfig$ImmutableState.register(ResourceConfig.java:257)
WARNING:   StandardWrapperValve[com.insame.service.ApplicationConfig]: Allocate exception for servlet com.insame.service.ApplicationConfig
java.lang.IllegalStateException: The resource configuration is not modifiable in this context.
    at org.glassfish.jersey.server.ResourceConfig$ImmutableState.register(ResourceConfig.java:257)
    at org.glassfish.jersey.server.ResourceConfig$ImmutableState.register(ResourceConfig.java:205)
    at org.glassfish.jersey.server.ResourceConfig.register(ResourceConfig.java:435)
    at org.glassfish.jersey.servlet.WebComponent.<init>(WebComponent.java:261)
    at org.glassfish.jersey.servlet.ServletContainer.init(ServletContainer.java:167)
    at org.glassfish.jersey.servlet.ServletContainer.init(ServletContainer.java:349)

环境

  • Netbeans7.3.1
  • 玻璃鱼 4.0
  • 带有 Glassfish 4.0 的 Jersey 2
4

6 回答 6

45

为了在您的 Jersey 应用程序中使用 multipart，您需要在您的应用程序中注册MultiPartFeature，即：

public class ApplicationConfig extends Application {

    public Set<Class<?>> getClasses() {
        final Set<Class<?>> resources = new HashSet<Class<?>>();

        // Add your resources.
        resources.add(UploadFileService.class);

        // Add additional features such as support for Multipart.
        resources.add(MultiPartFeature.class);

        return resources;
    }
}

有关更多信息，请参阅Jersey 用户指南中的Multipart部分。

对于您面临的第二个问题，请尝试重新启动 GlassFish 服务器，我不确定 NetBeans 在更改后如何重新加载 Jersey 应用程序（如果这没有帮助，请发布您的ApplicationConfig.

于 2013-08-15T15:49:36.573 回答
33

我有同样的问题，想避免创建自定义应用程序类。它没有很好的文档记录，但是如果你想添加 Multipart 功能，你所要做的就是将它添加到你的 web.xml jersey servlet 配置中：

<init-param>
    <param-name>jersey.config.server.provider.classnames</param-name>
    <param-value>org.glassfish.jersey.filter.LoggingFilter;org.glassfish.jersey.media.multipart.MultiPartFeature</param-value>
</init-param>

我还添加了一个日志过滤器。

于 2014-08-14T15:54:22.053 回答
2

如果您使用的是 jetty 服务器和 jersey servlet，那么您可以通过在已启动 jetty 服务器的主类中添加以下代码来解决此问题，

ServletHolder jerseyServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*"); jerseyServlet.setInitOrder(0);

      // Tells the Jersey Servlet which REST service/classes to load.
      jerseyServlet
              .setInitParameter(
                      "jersey.config.server.provider.classnames",
                      <Your entry point class's canonical name>
                              + ";org.glassfish.jersey.media.multipart.MultiPartFeature");
于 2016-02-02T12:58:30.363 回答
0

只是轻微的澄清

利用

import org.glassfish.jersey.media.multipart.MultiPartFeature
import org.glassfish.jersey.media.multipart.FormDataContentDisposition;
import org.glassfish.jersey.media.multipart.FormDataParam;

不是

com.sun.jersey.*

仅在使用时才为我工作org.glassfish.jersey.media.multipart.*

在 ApplicationConfig 中，只需将 MultiPartFeature 注册为

import org.glassfish.jersey.media.multipart.MultiPartFeature;

@javax.ws.rs.ApplicationPath("webresources")
public class ApplicationConfig extends Application {

    @Override
    public Set<Class<?>> getClasses() {
        Set<Class<?>> resources = new java.util.HashSet<>();
        resources.add(UploadFileService.class);
        resources.add(MultiPartFeature.class);
        return resources;
    }
}
于 2014-08-19T11:20:16.187 回答
0

我正在使用泽西岛 1.9.1。org.glassfish...... 适用于 Jersey 2。对于 Jersey 1，您最好使用 com.sun... 类。

于 2017-03-23T12:54:18.953 回答
-1

如果您希望使用注释，则可以使用 FormDataMultiPart 的 @FormDataParam("file") 等效项。

使用如下示例代码提取：

public Response uploadFile( **@FormDataParam("file")** InputStream fileInputStream,
             @FormDataParam("file") FormDataContentDisposition contentDispositionHeader) {
于 2017-03-22T18:59:15.030 回答