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我有以下代码来绘制任意弧：

void CenteredArc::drawPolygonArc(float radius, float thickness, float startAngle, float arcAngle) {
    float num_segments = 360.0;

    float radiusOuter = radius + thickness / 2;
    float radiusInner = radius - thickness / 2;
    float theta = arcAngle / num_segments; 
    float tangetial_factor = tanf(theta);//calculate the tangential factor 

    float radial_factor = cosf(theta);//calculate the radial factor 

    float xxOuter = radiusOuter * cosf(startAngle);
    float yyOuter = radiusOuter * sinf(startAngle);
    float xxInner = radiusInner * cosf(startAngle);
    float yyInner = radiusInner * sinf(startAngle);  

    float prevXXOuter = -1;
    float prevYYOuter = -1;
    float prevXXInner = -1;
    float prevYYInner = -1;

    glPolygonMode(GL_FRONT, GL_FILL);
    for(int ii = 0; ii < num_segments; ii++) 
    { 
        if (prevXXOuter != -1) {
            glBegin(GL_POLYGON);
                glVertex2f(prevXXOuter, prevYYOuter);
                glVertex2f(xxOuter,     yyOuter);
                glVertex2f(xxInner,     yyInner);
                glVertex2f(prevXXInner, prevYYInner);
            glEnd();
        }

        //calculate the tangential vector 
        //remember, the radial vector is (x, y) 
        //to get the tangential vector we flip those coordinates and negate one of them 

        float txOuter = -yyOuter; 
        float tyOuter =  xxOuter; 
        float txInner = -yyInner; 
        float tyInner =  xxInner; 

        //add the tangential vector 

        prevXXOuter = xxOuter;
        prevYYOuter = yyOuter;
        prevXXInner = xxInner;
        prevYYInner = yyInner;

        xxOuter += txOuter * tangetial_factor; 
        yyOuter += tyOuter * tangetial_factor; 
        xxInner += txInner * tangetial_factor; 
        yyInner += tyInner * tangetial_factor; 

        //correct using the radial factor 
        xxOuter *= radial_factor; 
        yyOuter *= radial_factor; 
        xxInner *= radial_factor; 
        yyInner *= radial_factor; 
    }
}

但是，我希望弧从一端指定的厚度开始，然后逐渐减小到另一端的厚度为零。有什么建议么？

编辑：我没有使用GL_LINE_STRIP，因为我试图避免像这样重叠的线条和间隙：

在此处输入图像描述

4

1 回答 1

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我会使用 a line stripwith reduction glLineWidth。

这是我的实现，它不会逐渐减少，lineWidth但可以对其进行修改。对不起，额外的东西，它来自我的游戏引擎。

for(int i=0;i<arcs().size();i++)
{
        Entities::Arc temp = arcs().at(i);
        glLineWidth(temp.LW.value); // change LWidth

        glColor3f( temp.CL.R, temp.CL.G, temp.CL.B );

        // theta is now calculated from the arc angle instead, the
        // - 1 part comes from the fact that the arc is open
        float theta = temp.A.value*DEG2RAD / float(WW_SPLINE_ACCURACY - 1);

        float tan = tanf(theta);
        float cos = cosf(theta);

        // we are now at the starting angle
        double x = temp.R.value * cosf(temp.A.value*DEG2RAD);
        double y = temp.R.value * sinf(temp.A.value*DEG2RAD);

        // since the arc is not a closed curve, this is a strip now
        glBegin(GL_LINE_STRIP);
        for(int ii = 0; ii < WW_SPLINE_ACCURACY; ii++)
        {
            glVertex2d(x + temp.C.X, y + temp.C.Y);
            double tx = -y;
            double ty = x;
            x += tx * tan;
            y += ty * tan;
            x *= cos;
            y *= cos; //y = ( y + (ty*tan) )*cos;
        }
    glEnd();
    glLineWidth(WW_DEFAULT_LWIDTH); // reset LWidth
}

我也使用了这些值

#define WW_SPLINE_ACCURACY  72 // 72 for extra smooth arcs/circles, 32 minimum
#define WW_BEZIER_ACCURACY  20

/* Math stuff */
#define DEG2RAD 3.14159/180
#define PI  3.1415926535897932384626433832795;

...

glDisable(GL_TEXTURE_2D);
glDisable(GL_DEPTH_TEST);
glDisable(GL_COLOR_MATERIAL);
glEnable (GL_LINE_SMOOTH);
glEnable (GL_BLEND);
//glBlendFunc (GL_SRC_ALPHA, GL_ONE_MINUS_SRC_ALPHA);
glHint (GL_LINE_SMOOTH_HINT, GL_DONT_CARE);
glEnable(GL_POLYGON_SMOOTH);
glClearColor(0.188f, 0.169f, 0.329f, 1.0f); //#302b54

因为我是为一家公司写的，所以我不允许发布完整的源代码，但分享一两部分不会伤害任何人：D

于 2013-08-14T17:30:41.227 回答