我希望你能帮助我。
我需要在 HH_Solution_Audit 表中显示记录——如果 2 名或更多员工在 10 分钟内进入房间。以下是要求:
- 仅显示时间戳 (LAST_UPDATED) 间隔小于或等于 10 分钟的事件。因此,我必须将当前行与下一行和上一行进行比较,以检查它们的 DATEDIFF 是否小于或等于 10 分钟。我已经完成了这部分。
- 如果房间内的不同 STAFF_GUID 少于或等于 10 分钟的数量至少为 2,则仅显示记录。
HH_Solution_Audit 表详细信息:
- 身份证 - PK
- STAFF_GUID - 员工 ID
- LAST_UPDATED - 员工进入房间的日期时间
这是我到目前为止所得到的。这仅满足要求#1。
CREATE TABLE HH_Solution_Audit (
ID INT PRIMARY KEY,
STAFF_GUID NVARCHAR(1),
LAST_UPDATED DATETIME
)
GO
INSERT INTO HH_Solution_Audit VALUES (1, 'b', '2013-04-25 9:01')
INSERT INTO HH_Solution_Audit VALUES (2, 'b', '2013-04-25 9:04')
INSERT INTO HH_Solution_Audit VALUES (3, 'b', '2013-04-25 9:13')
INSERT INTO HH_Solution_Audit VALUES (4, 'a', '2013-04-25 10:15')
INSERT INTO HH_Solution_Audit VALUES (5, 'a', '2013-04-25 10:30')
INSERT INTO HH_Solution_Audit VALUES (6, 'a', '2013-04-25 10:33')
INSERT INTO HH_Solution_Audit VALUES (7, 'a', '2013-04-25 10:41')
INSERT INTO HH_Solution_Audit VALUES (8, 'a', '2013-04-25 11:02')
INSERT INTO HH_Solution_Audit VALUES (9, 'a', '2013-04-25 11:30')
INSERT INTO HH_Solution_Audit VALUES (10, 'a', '2013-04-25 11:45')
INSERT INTO HH_Solution_Audit VALUES (11, 'a', '2013-04-25 11:46')
INSERT INTO HH_Solution_Audit VALUES (12, 'a', '2013-04-25 11:51')
INSERT INTO HH_Solution_Audit VALUES (13, 'a', '2013-04-25 12:24')
INSERT INTO HH_Solution_Audit VALUES (14, 'b', '2013-04-25 12:27')
INSERT INTO HH_Solution_Audit VALUES (15, 'b', '2013-04-25 13:35')
DECLARE @numOfPeople INT = 2,
--minimum number of people that must be inside
--the room for @lengthOfStay minutes
@lengthOfStay INT = 10,
--number of minutes of stay
@dateFrom DATETIME = '04/25/2013 00:00',
@dateTo DATETIME = '04/25/2013 23:59';
WITH cteSource AS
(
SELECT ID, STAFF_GUID, LAST_UPDATED,
ROW_NUMBER() OVER (ORDER BY LAST_UPDATED) AS row_num
FROM HH_SOLUTION_AUDIT
WHERE LAST_UPDATED >= @dateFrom AND LAST_UPDATED <= @dateTo
)
SELECT [current].ID, [current].STAFF_GUID, [current].LAST_UPDATED
FROM
cteSource AS [current]
LEFT OUTER JOIN
cteSource AS [previous] ON [current].row_num = [previous].row_num + 1
LEFT OUTER JOIN
cteSource AS [next] ON [current].row_num = [next].row_num - 1
WHERE
DATEDIFF(MINUTE, [previous].LAST_UPDATED, [current].LAST_UPDATED)
<= @lengthOfStay
OR
DATEDIFF(MINUTE, [current].LAST_UPDATED, [next].LAST_UPDATED)
<= @lengthOfStay
ORDER BY [current].ID, [current].LAST_UPDATED
运行查询返回 ID:
1、2、3、5、6、7、10、11、12、13、14
满足要求 #1 前一行、当前行和当前行之间的间隔小于或等于 10 分钟下一行。
你能帮我解决第二个要求吗?如果应用了,返回的 ID 应该只有:
13, 14