0

你能帮我实现这个 XSLT 转换吗？这更像是扭转关系...

我有 Offer/Offer*/TrimLine*/PRNumber* ---> 我想将其转换为 PRNumbers/PRNumber*/TrimLine*/Offer*

输入：

    <offerStructures>
    <offerStructure>
        <productId>1</productId>
        <brandName>OS</brandName>
        <trimLines>
            <trimLine>
                <productId>12</productId>
                <trimLineName>12TL</trimLineName>
                <prNumbers>
                    <prNumber>
                        <productId>1</productId>
                        <countryCode>IN</countryCode>
                        <brandName>OKI</brandName>
                    </prNumber>
                    <prNumber>
                        <productId>2</productId>
                        <countryCode>US</countryCode>
                        <brandName>LOP</brandName>
                    </prNumber>
                </prNumbers>
            </trimLine>
            <trimLine>
                <productId>13</productId>
                <trimLineName>13TL</trimLineName>
                <prNumbers>
                    <prNumber>
                        <productId>1</productId>
                        <countryCode>IN</countryCode>
                        <brandName>PYU</brandName>
                    </prNumber>
                    <prNumber>
                        <productId>3</productId>
                        <countryCode>AU</countryCode>
                        <brandName>ABC</brandName>
                    </prNumber>
                </prNumbers>
            </trimLine>
        </trimLines>
    </offerStructure>
    ../Multiple Offer Structure
</offerStructures>

所需输出：

<prNumbers>
    <prNumber>
        <productId>1</productId>
        <countryCode>IN</countryCode>
        <brandName>PYU</brandName>
        <trimLine>
            <productId>13</productId>
            <trimLineName>13TL</trimLineName>
            <offerStructure>
                <productId></productId>
            </offerStructure>
            <offerStructure>
                <productId></productId>
            </offerStructure>
        </trimLine>
        <trimLine>
            <productId>12</productId>
            <trimLineName>12TL</trimLineName>
        </trimLine>
    </prNumber>
    <prNumber>
        <productId>2</productId>
        <countryCode>US</countryCode>
        <brandName>LOP</brandName>
        <trimLine>
            <productId>12</productId>
            <trimLineName>12TL</trimLineName>
            <offerStructure>
                <productId></productId>
            </offerStructure>
        </trimLine>
    </prNumber>
    <prNumber>
        <productId>3</productId>
        <countryCode>AU</countryCode>
        <brandName>ABC</brandName>
        <trimLine>
            <productId>13</productId>
            <trimLineName>13TL</trimLineName>
        </trimLine>
    </prNumber>
</prNumbers>

谢谢

4

1 回答 1

0

它可能不是你需要的 100%（因为你对你的要求相当模糊），但是

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output omit-xml-declaration="yes" indent="yes" />

  <xsl:key name="kPrNumber" match="prNumber" use="productId" />

  <xsl:template match="/">
    <prNumbers>
      <xsl:apply-templates select="//prNumber" mode="group" />
    </prNumbers>
  </xsl:template>

  <xsl:template match="prNumber" mode="group">
    <xsl:variable name="thisGroup" select="key('kPrNumber', productId)" />   

    <xsl:if test="generate-id() = generate-id($thisGroup[1])">
      <xsl:copy>
        <xsl:copy-of select="productId" />
        <xsl:copy-of select="countryCode" />
        <xsl:copy-of select="brandName" />
        <xsl:apply-templates select="$thisGroup/ancestor::trimLine" />
      </xsl:copy>
    </xsl:if>
  </xsl:template>

  <xsl:template match="trimLine">
    <xsl:copy>
      <xsl:copy-of select="productId" />
      <xsl:copy-of select="trimLineName" />
      <xsl:apply-templates select="ancestor::offerStructure" />
    </xsl:copy>
  </xsl:template>

  <xsl:template match="offerStructure">
    <xsl:copy>
      <xsl:copy-of select="productId" />
      <xsl:copy-of select="brandName" />
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

给你

<prNumbers>
  <prNumber>
    <productId>1</productId>
    <countryCode>IN</countryCode>
    <brandName>OKI</brandName>
    <trimLine>
      <productId>12</productId>
      <trimLineName>12TL</trimLineName>
      <offerStructure>
        <productId>1</productId>
        <brandName>OS</brandName>
      </offerStructure>
    </trimLine>
    <trimLine>
      <productId>13</productId>
      <trimLineName>13TL</trimLineName>
      <offerStructure>
        <productId>1</productId>
        <brandName>OS</brandName>
      </offerStructure>
    </trimLine>
  </prNumber>
  <prNumber>
    <productId>2</productId>
    <countryCode>US</countryCode>
    <brandName>LOP</brandName>
    <trimLine>
      <productId>12</productId>
      <trimLineName>12TL</trimLineName>
      <offerStructure>
        <productId>1</productId>
        <brandName>OS</brandName>
      </offerStructure>
    </trimLine>
  </prNumber>
  <prNumber>
    <productId>3</productId>
    <countryCode>AU</countryCode>
    <brandName>ABC</brandName>
    <trimLine>
      <productId>13</productId>
      <trimLineName>13TL</trimLineName>
      <offerStructure>
        <productId>1</productId>
        <brandName>OS</brandName>
      </offerStructure>
    </trimLine>
  </prNumber>
</prNumbers>

请注意，在第一个<prNumber>它给你<brandName>OKI</brandName>。这是因为您的输入样本有几个用于 productId 1 的麸皮名称可供选择，这使事情变得模棱两可。

于 2013-08-14T13:59:52.940 回答