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我有这个查询，它运行良好，但我想首先根据最接近的结果进行排序：

    SELECT DISTINCT Name, Address, City, State, Zip FROM Clinics WHERE ZIP IN 
   (SELECT h.zipcode FROM zipcodes 
    g JOIN zipcodes h on g.zipcode <> 
    h.zipcode AND g.zipcode = '32244' AND h.zipcode <> '32244'
     WHERE g.GeogCol1.STDistance(h.GeogCol1)<=(100 * 1609.344)) 
    UNION ALL SELECT DISTINCT Name, Address, City, State, Zip 
    FROM Clinics WHERE ZIP = '32244'

我试过这个：

SELECT DISTINCT Name, Address, City, State, Zip FROM Clinics 
WHERE ZIP IN (SELECT h.zipcode FROM zipcodes 
g JOIN zipcodes h on g.zipcode <> 
h.zipcode AND g.zipcode = '32244' AND h.zipcode <> '32244'
WHERE g.GeogCol1.STDistance(h.GeogCol1)<=(100 * 1609.344)) 
UNION ALL SELECT DISTINCT Name, Address, City, State, Zip
FROM Clinics WHERE ZIP = '32244' 
order by g.GeogCol1.STDistance(h.GeogCol1) DESC

但它给了我一个错误：

找不到列“g”或用户定义的函数或聚合“g.GeogCol1.STDistance”，或者名称不明确。

我这样做对吗？

4

1 回答 1

4

首先，您需要确定距离：

SELECT h.zipcode, (g.GeogCol1.STDistance(h.GeogCol1) / 1609.344) dist
  FROM dbo.zipcodes h CROSS JOIN dbo.zipcodes g
 WHERE g.zipcode = '32244'

这会将相关邮政编码与所有邮政编码配对，包括其本身。（我将加入包含到相同的邮政编码中，因为这样我就不必再做UNION后面的事情了。）

下一步是过滤距离：

WITH ZipPairs AS(
  SELECT h.zipcode, (g.GeogCol1.STDistance(h.GeogCol1) / 1609.344) dist
    FROM dbo.zipcodes h CROSS JOIN dbo.zipcodes g
   WHERE g.zipcode = '32244'
), CloseZips AS(
  SELECT *
    FROM ZipPairs
   WHERE Dist < 100*1609.344
)
SELECT * FROM CloseZips;

之后，您可以加入诊所并按距离排序：

WITH ZipPairs AS(
  SELECT h.zipcode, (g.GeogCol1.STDistance(h.GeogCol1) / 1609.344) dist
    FROM dbo.zipcodes h CROSS JOIN dbo.zipcodes g
   WHERE g.zipcode = '32244'
), CloseZips AS(
  SELECT *
    FROM ZipPairs
   WHERE Dist < 100*1609.344
)
SELECT C.*,Z.Dist
  FROM dbo.Clinics AS C
  JOIN CloseZips Z
    ON C.Zip = Z.zipcode
 ORDER BY Z.Dist;
于 2013-08-14T01:05:08.340 回答