22

I have a HTML5 web application with numerous user-entered fields, and I would like to do some client-side validation on those fields in javascript before sending them to the server. Easy right? Just use JQuery validation plugin --- http://jqueryvalidation.org/

But there's a catch. My web app has no forms. There is no submit anywhere in the HTML. Instead there's a JQuery change handler on every user-changeable element, and when the user changes the value of one of those element, an AJAX call is made. (This nonstandard user interaction architecture makes sense for this application.)

I would like to validate the field before the AJAX call, and use the JQuery validation plugin to do that. But I can't figure out how.

Is it possible to use the JQuery validation plugin without a submit anywhere? How would I do this? Or is another approach better?

4

5 回答 5

54

首先，也是最重要的，您必须将输入元素包装在<form></form>标签中，以便 jQuery Validate 插件运行。但是，不需要提交按钮。

其次，您可以使用该.valid()方法以编程方式触发任何或所有元素的有效性测试，而无需提交按钮。

$(document).ready(function() {

    $('#myform').validate({  // initialize the plugin on your form.
        // rules, options, and/or callback functions
    });

    // trigger validity test of any element using the .valid() method.
    $('#myelement').valid();

    // trigger validity test of the entire form using the .valid() method.
    $('#myform').valid();

    // the .valid() method also returns a boolean...
    if ($('#myform').valid()) {
        // something to do if form is valid
    }

});

演示：http: //jsfiddle.net/URQGG/

于 2013-08-13T23:48:10.203 回答
3

您必须将字段包装在表单中才能使用验证插件，无论如何这是一个好习惯。此外，您可以以编程方式调用插件的验证，并通过执行以下操作检查表单是否有效：

var $form = $('#your_form'),
    validator = $form.validate({...});

//validate the form
validator.form();

//check if the form is valid 
if ($form.valid()) {
    //form is valid
}

有关更多选项，请查看文档。

于 2013-08-13T22:44:05.967 回答
1

我创建了一个小帮手。只需添加这行代码，然后您就可以在任何地方使用任何按钮。

$("body [data-submit-form]").on("click", function (event) {
    $("#" + $(event.target).data('submit-form')).valid();
});

<form id="component-form">

</form>

<button data-submit-form="component-form">Button</button>

说明：jquery 代码侦听具有属性“data-submit-form”的元素的所有点击，在侦听器中提取数据属性，然后我触发匹配表单上的有效方法。

注意：如果您想在表单有效的情况下提交表单，请使用以下代码：

$("body [data-submit-form]").on("click", function (event) {
    var form = $("#" + $(event.target).data('submit-form'));
    if (form.valid()) {
        form.submit();
    }
});
于 2017-12-04T00:45:39.217 回答
0

将此代码用于两个示例字段电子邮件和密码：- 

<head>
    <script src="jquery-3.4.0.min.js"></script>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <meta http-equiv="X-UA-Compatible" content="ie=edge">
    <title>Document</title>
    <style>
        #txt1{

        margin-left:23px;
        border-radius: 12px;
       }
       #txt2{
        border-radius: 12px;
       }
       #btn1{
        border-radius: 12px;
        width: 8em;  height: 2em;
        cursor:pointer;
        background-color: #008CBA;
       }
       #lbl1,#lbl2{
        font-family: "Comic Sans MS", cursive, sans-serif;
        color:red;
       }
    </style>
</head>

<body>
    <div class="container">
        <form>
            <center> <label id="lbl1">Email: </label><input type="text" id="txt1"></center></input><br>
            <center><label id="lbl2">Password: </label><input type="password" id="txt2"></center></input>
            <br><br>
            <center><input type="button" id="btn1" name="btn1" value="Login" style="color:darkblue;font-size:15px;"></center></input>
        </form>

    </div>
    <script>
        $(document).ready(function () {
            $('#btn1').click(function () {
                var email = $('#txt1').val();
                var pass = $('#txt2').val();
                if (email == '') {
                    $('input[type="text"]').css("border", "2px solid red");
                    $("#txt1").parent().after("<div class='validation' style='color:red;margin-left:93px;'><center>Please enter email address</center></div>");
                    alert("hi");
                }
                else {

                }
                if (pass == '') {
                    $('input[type="password"]').css("border", "2px solid red");
                    $("#txt2").parent().after("<div class='validationp' style='color:red;margin-left:70px;'><center>Please enter password</center></div>");
                }
                $('input[type="text"]').keydown(function () {
                    $('input[type="text"]').css("border", "");
                    $(".validation").remove();
                });
                $('input[type="password"]').keydown(function () {
                    $('input[type="password"]').css("border", "");
                    $(".validationp").remove();

                });

            });
        });

    </script>
</body>

</html>
于 2019-04-30T10:34:17.993 回答
-4

只需使用调用表单提交方法jquery 

$("#formId").submit()

这将验证整个表单，就像我们单击提交按钮时一样

于 2019-05-21T12:14:22.523 回答