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我想发出 ajax 请求以从数据库中获取一些数据,然后将该数据发送到另一个文件,该文件将返回另一个结果。似乎不起作用,第一个 Ajax 请求工作正常,但是当第一个返回结果时触发的第二个请求什么也不做。

var http = getHTTPObject();
    var http2 = getHTTPObject();
    ids = fetchSelection().toString();

    //Make button animate, visual aid that it is working
    obj.src = "http://localhost/nightclub_photography/images/buttons/"+dir+"_animated.gif";

    http.onreadystatechange = function() 
    {
        if (http.readyState == 4 && http.status == 200) {
            http2.onreadystatechange = function() 
            {
                if (http2.readyState == 4 && http2.status == 200)
                {
                    alert("hello");
                }
            }
            http2.open("GET", "http://localhost/nightclub_photography/net/test2.aspx");
            http2.send();
        }
    }
    http.open("GET", "http://localhost/nightclub_photography/asp/returnDatabaseData.asp?ids="+ids);
    http.send();
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1 回答 1

1

test.aspx 返回一个错误,因为我忘记传递它正在寻找的 URL 变量。我傻了,谢谢大家!

于 2013-08-13T20:43:52.267 回答