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我正在尝试从一个大的数据帧中制作一个较小的数据帧，这取决于 2 个数据帧中“row.ID”列中的相似行。

我一直在尝试申请match()，subset()但merge()从未得到我需要的结果。

这是我的数据框的样子

    file1<- structure(list(row.ID = c(1, 22, 51, 31, 231, 21, 551, 13, 10, 
    11, 12, 83, 84, 86, 87, 89, 120, 91, 92, 311, 94, 187, 98), Col0 = c(1, 
    2, 3, 4, 5, 6, 12, 13, 15, 16, 18, 126, 128, 131, 132, 135, 136, 
    137, 139, 140, 141, 143, 148), V1 = c(238.27, 294.39, 413.3, 
    853.24, 7.06, 8.987, 41.73, 39.232, 11.151, 13.472, 8.041, 8.057, 
    7.961, 7.43, 8.047, 334.54, 229.03, 265.36, 354.49, 151.25, 237.75, 
    901.24, 280.27), V2 = c(7.686, 6.846, 10.08, 6.666, 26.741, 29.358, 
    12.885, 11.982, 22.898, 12.75, 21.041, 28.87, 12.316, 19.778, 
    71.023, 11.151, 13.472, 8.041, 8.057, 7.961, 7.43, 8.047, 9.342
    ), V3 = c(19.063, 25.17, 29.626, 79.233, 38.952, 42.658, 13.015, 
    12.244, 30.044, 17.862, 33.345, 44.065, 18.713, 31.822, 113.207, 
    22.898, 12.75, 21.041, 28.87, 12.316, 19.778, 71.023, 21.963), 
        V4 = c(31.814, 43.349, 42.989, 125.904, 28.853, 30.392, 16.483, 
        16.335, 25.648, 13, 22.347, 30.699, 13.699, 21.409, 75.841, 
        30.044, 17.862, 33.345, 44.065, 18.713, 31.822, 113.207, 
        30.905), V5 = c(19.398, 26.443, 29.687, 85.433, 43.737, 46.906, 
        12.413, 12.409, 32.337, 18.715, 36.953, 49.575, 21.079, 35.973, 
        124.988, 25.648, 13, 22.347, 30.699, 13.699, 21.409, 75.841, 
        21.904), V6 = c(35.325, 48.986, 45.76, 334.54, 0.75, 12, 
        241.34, 258.34, 282.4, 377.46, 30.392, 16.483, 0.648, 0.618, 
        0.634, 32.337, 18.715, 36.953, 49.575, 21.079, 35.973, 124.988, 
        33.416), V7 = c(0.615, 294.39, 413.3, 1.001, 1.051, 17, 1.011, 
        0.985, 0.974, 1.016, 46.906, 12.413, 377.46, 500.76, 470.78, 
        334.54, 0.75, 0.638, 0.656, 0.648, 0.618, 0.634, 0.732), 
        V8 = c(1.026, 1.008, 1.049, 10, 21, 12, 227.31, 241.34, 258.34, 
        282.4, 377.46, 500.76, 1.016, 1.085, 1.02, 1.001, 1.051, 
        1.01, 1.001, 0.985, 0.994, 1.011, 1.03), V9 = c(0.626, 46.906, 
        12.413, 12.409, 32.337, 18.715, 17, 0.678, 0.664, 0.656, 
        0.723, 0.721, 0.724, 1.374, 1.361, 0.855, 0.765, 0.677, 0.698, 
        0.721, 0.669, 0.677, 0.73), V10 = c(1.14, 377.46, 500.76, 
        470.78, 334.54, 0.75, 12, 241.34, 258.34, 282.4, 377.46, 
        30.392, 16.483, 16.335, 25.648, 13, 0.648, 0.618, 0.634, 
        32.337, 18.715, 36.953, 49.575), V11 = c(31, 1.016, 1.085, 
        1.02, 1.001, 1.051, 17, 1.011, 0.985, 0.974, 1.016, 46.906, 
        12.413, 12.409, 32.337, 18.715, 377.46, 500.76, 470.78, 334.54, 
        0.75, 0.638, 0.656), V12 = c(17, 32, 30, 12, 10, 21, 12, 
        227.31, 241.34, 258.34, 282.4, 377.46, 500.76, 470.78, 334.54, 
        0.75, 1.016, 1.085, 1.02, 1.001, 1.051, 1.01, 1.001), V13 = c(31, 
        43, 43, 132, 21, 0.99, 1, 1.016, 1.011, 0.985, 0.974, 1.016, 
        1.085, 1.02, 1.001, 1.051, 0.724, 1.374, 1.361, 0.855, 0.765, 
        0.677, 0.698), V14 = c(17, 21, 31, 0.985, 0.974, 1.016, 1.085, 
        9, 16, 17, 23, 32, 30, 12, 10, 21, 16.483, 16.335, 25.648, 
        13, 1.101, 1.12, 1.127), V15 = c(9, 9, 25, 17, 23, 32, 30, 
        0, 8, 8, 21, 6, 21, 6, 6, 7, 12.413, 12.409, 32.337, 18.715, 
        17, 33, 44)), .Names = c("row.ID", "Col0", "V1", "V2", "V3", 
    "V4", "V5", "V6", "V7", "V8", "V9", "V10", "V11", "V12", "V13", 
    "V14", "V15"), row.names = c(NA, 23L), class = "data.frame")

file2<- structure(list(row.ID = c(83, 94, 98), X = c(1077, 1171, 1205
), V1 = c(-1.278147106, -0.895961572, -1.491168551), NO.YES = structure(c(1L, 
1L, 1L), .Label = "NO", class = "factor"), YES.NO = structure(c(1L, 
1L, 1L), .Label = "YES", class = "factor"), P.Y = c(0.168275205, 
0.264104166, 0.128155717), P.NO = c(0.831724795, 0.735895834, 
0.871844283)), .Names = c("row.ID", "X", "V1", "NO.YES", "YES.NO", 
"P.Y", "P.NO"), row.names = c(NA, 3L), class = "data.frame")

我想要的输出将是具有以下结构的数据框。

row ID  Col0    V1  V2  .   .   V15                                             
83  126 8.057   28.87   .   .   6                                                   
94  141 237.75  7.43    .   .   17                     
98  148 280.27  9.342   .   .   44

我主要是在尝试合并（），比如

mylist <- merge(file1,file2,by="row.ID")

但它造成了很多麻烦。有什么简单的命令可以做到这一点吗？

4

2 回答 2

1

merge第一个代码为文件 1 提供了 row.ID 中的哪些行位于文件 2 的 row.ID 行中。因此，当您使用命令时，它不会为您提供文件 2 的列。您可以对 k2 使用单独的类似代码，如下所示来生成与 row.ID 匹配的行的 file2。

 k1<-file1[file1$row.ID %in% file2$row.ID,]
    > k1
       row.ID Col0      V1     V2     V3     V4     V5     V6     V7      V8    V9    V10    V11     V12   V13    V14 V15
    12     83  126   8.057 28.870 44.065 30.699 49.575 16.483 12.413 500.760 0.721 30.392 46.906 377.460 1.016 32.000   6
    21     94  141 237.750  7.430 19.778 31.822 21.409 35.973  0.618   0.994 0.669 18.715  0.750   1.051 0.765  1.101  17
    23     98  148 280.270  9.342 21.963 30.905 21.904 33.416  0.732   1.030 0.730 49.575  0.656   1.001 0.698  1.127  44

k2<-file2[file2$row.ID %in% file1$row.ID,]

> k2
  row.ID    X         V1 NO.YES YES.NO       P.Y      P.NO
1     83 1077 -1.2781471     NO    YES 0.1682752 0.8317248
2     94 1171 -0.8959616     NO    YES 0.2641042 0.7358958
3     98 1205 -1.4911686     NO    YES 0.1281557 0.8718443

注意：如果使用merge，则两个文件中都有 V1，因此它会创建V1.x和V1.y.

> merge(file1,file2,"row.ID")
  row.ID Col0    V1.x     V2     V3     V4     V5     V6     V7      V8    V9    V10    V11     V12   V13    V14 V15    X       V1.y NO.YES
1     83  126   8.057 28.870 44.065 30.699 49.575 16.483 12.413 500.760 0.721 30.392 46.906 377.460 1.016 32.000   6 1077 -1.2781471     NO
2     94  141 237.750  7.430 19.778 31.822 21.409 35.973  0.618   0.994 0.669 18.715  0.750   1.051 0.765  1.101  17 1171 -0.8959616     NO
3     98  148 280.270  9.342 21.963 30.905 21.904 33.416  0.732   1.030 0.730 49.575  0.656   1.001 0.698  1.127  44 1205 -1.4911686     NO
  YES.NO       P.Y      P.NO
1    YES 0.1682752 0.8317248
2    YES 0.2641042 0.7358958
3    YES 0.1281557 0.8718443
于 2013-08-13T15:04:07.617 回答
1

这是@James Pringle 使用 data.tables 的答案（在上面的评论中）：

file1dt <- data.table(file1)
file2dt <- data.table(file2)
setkey(file1dt,row.ID)
file1dt[J(file2dt$row.ID)]

如果您想要两个文件中的列，您只需执行file1dt[file2dt]. OP 说“我的数据将一遍又一遍地与其他数据文件进行比较”，所以也许 data.tables （应该进行快速合并/连接）在这里会有所帮助。适用于 data.frames 的函数也适用于 data.tables。

于 2013-08-13T16:09:55.680 回答