1 scrollRight
不存在。scrollLeft
必须使用负数才能“向右滚动”
2 jqelem.scrollLeft(position)
--> 多次调用此函数后,您可能想知道为什么它不会再次滚动。那是因为它滚动到那个位置,它不会将滚动增加到偏移量。jqelem.scrollLeft(jqelem.scrollLeft() + offset)
您想让它根据当前滚动值继续滚动也是如此。
这是一个基于您发布的代码的工作示例:
JSFIDDLE:http: //jsfiddle.net/6dsTU/
HTML 代码:
<div id="wrap">
<div class="overview">
<span class="largeNext"></span><span class="largePrev"></span>
<div class="cnt">LOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOOLOLOLOLOLOLOLOLOLOLOLLLOLLLOLOLOLOLOLLOLLOLOLOLO</div>
</div>
</div>
JS代码:
var selec = $('.cnt');
$('span.largeNext').on('click', function() {
var currscrl = selec.scrollLeft();
selec.scrollLeft(currscrl + 200);
})
$('span.largePrev').on('click', function() {
var currscrl = selec.scrollLeft();
selec.scrollLeft(currscrl - 200);
})
代码:
.cnt
{
overflow:hidden;
}
.wrap
{
width: 10000px;
}
.largeNext
{
left:50px;
top:50px;
width: 50px;
height: 50px;
position:absolute;
border: 1px solid black;
}
.largePrev
{
left:0px;
top:50px;
width: 50px;
height: 50px;
position:absolute;
border: 1px solid blue;
}